Answer:
232°
Step-by-step explanation:
There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.
30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))
= (0, -30) +(-43.301, -25) = (-43.301, -55)
Then the angle from port is ...
arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle
The bearing of the ship from port is about 232°.
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<em>Comment on the problem statement</em>
The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.
Answer: 23600000
Step-by-step explanation:
9514 1404 393
Answer:
- sin(Ф) = (4/41)√41; csc(Ф) = (√41)/4
- cos(Ф) = (5/41)√41; sec(Ф) = (√41)/5
- tan(Ф) = 4/5; cot(Ф) = 5/4
Step-by-step explanation:
The mnemonic SOH CAH TOA can help you with three of the functions. Then you need to remember the relations between those and the other three.
Tan = Opposite/Adjacent
tan(Ф) = 4/5
This suggests you can draw a triangle like the one attached that has adjacent side 5 and opposite side 4. Then hypotenuse can be found from the Pythagorean theorem:
AC² = AB² +BC² = 5² +4² = 41
AC = √41 . . . . . hypotenuse
Then the other trig functions are ...
Sin = Opposite/Hypotenuse
sin(Ф) = 4/√41 = (4/41)√41
Cos = Adjacent/Hypotenuse
cos(Ф) = 5/√41 = (5/41)√41
And the reciprocal functions are ...
csc(Ф) = 1/sin(Ф) = (√41)/4
sec(Ф) = 1/cos(Ф) = (√41)/5
cot(Ф) = 1/tan(Ф) = 5/4
6 workers-9 jobs in 3 days
In one day 6 workers can do 3 jobs
In one day 1 worker can do 0.5 job
4 workers can so 2 jobs in a day
So. They can do 10 jobs in 5 days
15 / 20 = 0.75. The answer is 0.75
