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Serga [27]
3 years ago
9

What is the answer to 7/8 times 2/9

Mathematics
2 answers:
deff fn [24]3 years ago
6 0

Answer:

7/36

Step-by-step explanation:

7/8 x 2/9

=> Multiply the numerators and the denominators

=> 7 x 2 / 8 x 9

=> 14 / 72

=> 7/ 36

aleksandrvk [35]3 years ago
4 0

Answer:

the answer would be 7/36

You might be interested in
4x2 +9y2 = 72
Kamila [148]

Answer:

<h2>        \bold{\left(\dfrac{3}{13}\ ,\ \dfrac{4\sqrt{13}}{13}\right)\qquad\vee\qquad \left(\dfrac{3}{13}\ ,\ -\dfrac{4\sqrt{13}}{13}\right)}</h2>

Step-by-step explanation:

x - y² = -1     ⇒   - y² = - x - 1    ⇒    y² = x + 1   {x≥-1}

4x² + 9y² = 72

4x² + 9(x + 1)² = 72

4x² + 9(x² + 2x + 1) = 72

4x² + 9x² + 18x + 9 - 72 = 0

13x² + 18x - 63 = 0     ⇒   a = 13,  b = 18,  c = -63

x=\dfrac{-18\pm\sqrt{18^2-4\cdot13\cdot(-63)}}{2\cdot13}=\dfrac{-18\pm\sqrt{324+252}}{26}=\dfrac{-18\pm\sqrt{576}}{26}\\\\x=\dfrac{-18+24}{26}=\dfrac3{13}\qquad\vee\qquad x=\dfrac{-18-24}{26}=-\dfrac{21}{13}\\\\ y^2= x + 1\quad\iff\quad x\ge-1\\\\y^2=\dfrac3{13}+1\\\\ y^2=\dfrac{16}{13}\\\\y=\dfrac{4}{\sqrt{13}}=\dfrac{4\sqrt{13}}{13}\qquad\vee\qquad y=-\dfrac{4\sqrt{13}}{13}

4 0
3 years ago
Simplify 5(a - b) + 6(a + b) - 7(a - 2b)<br><br> 4a - 13b<br> 4a + 15b<br> 19ab
Natalka [10]
5(a - b) + 6(a + b) - 7(a - 2b) = 5a-5b+6a+6b-7a+14b= 4a + 15b

7 0
3 years ago
Sin(x)^4+ cos(x)^4=1/2
posledela
I'll assume that what was meant was \sin ^4 x + \cos ^4 x = \dfrac{1}{2}.

The exponent in the funny place is just an abbreviation:   \sin ^4 x = (\sin x)^4.

I hope that's what you meant. Let me know if I'm wrong.

Let's start from the old saw

\cos^2 x + \sin ^2x = 1

Squaring both sides,

(\cos^2 x + \sin ^2x)^2 = 1^2

\cos^4 x + 2 \cos ^2 x \sin ^2x +\sin ^4x = 1

\cos^4 x + \sin ^4x = 1 - 2 \cos ^2 x \sin ^2x

So now the original question 

\sin ^4 x + \cos ^4 x = \dfrac{1}{2}

becomes
1 - 2 \cos ^2 x \sin ^2x = \dfrac{1}{2}

4 \cos ^2 x \sin ^2x = 1

Now we use the sine double angle formula

\sin 2x = 2 \sin x \cos x

We square it to see

\sin^2 2x = 4\sin^2 x \cos^2 x = 1

Taking the square root,

\sin 2x = \pm 1

Not sure how you want it; we'll do it in degrees. 

When we know the sine of an angle, there's usually two angles on the unit circle that have that sine.  They're supplementary angles which add to 180^\circ.  But when the sine is 1 or -1 like it is here, we're looking at 90^\circ and -90^\circ, which are essentially their own supplements, slightly less messy. 

That means we have two equations:

\sin 2x = 1 = \sin 90^\circ

2x = 90^\circ + 360^\circ k \quad integer k

x = 45^\circ + 180^\circ k

or 


\sin 2x = -1 = \sin -90^\circ

2x = -90^\circ+ 360^\circ k

x = - 45^\circ + 180^\circ k

We can combine those for a final answer,

x = \pm 45^\circ + 180^\circ k \quad integer k

Check.  Let's just check one, how about

x=-45^\circ + 180^\circ = 135^\circ

\sin(135)= 1/\sqrt{2}

\sin ^4(135)=(1/\sqrt{2})^4 = 1/4

\cos ^4(135)=(-1/\sqrt{2})^4 = 1/4

\sin ^4(135^\circ) +\cos ^4(135^\circ) = 1/2 \quad\checkmark


6 0
3 years ago
I need answers fast, I have other questions on my account btw. Thanks
rjkz [21]

Answer:

X=4

Step-by-step explanation:

It is vertical so it is X=__.  It is on x=4 so that is the answer

3 0
4 years ago
Solve |x+6| - 7 = 8<br> plzzzzzz
Nana76 [90]

Answer:

X=9

Step-by-step explanation:

9+6=15

15-7=8

Absolute value equals a positive

5 0
3 years ago
Read 2 more answers
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