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3 years ago

11

I may need some help

2 answers:

VikaD [51]3 years ago

8 0

i have to poop hhhhhjhhjhjhjhjhjhjhh

Evgen [1.6K]3 years ago

7 0

Heres a trick in order identify if a graph is a function or not. Draw a line vertically over the graph (or use a ruler instead) and see whether there are two or more points that touch the line. This is called the vertical line test. So for the first graph, you can already tell that if you were to draw a line over the graph you wont get points that overlap, therefore it is a function. Hope this helps!

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The rectangle room is 2 times as long as it wide and its perimeter is 30 meters. Find the dimensions of the room.

Pachacha [2.7K]

Answer:
l = 10 m
w = 5 m

Steps:
Set equations:
l = 2w
30 = 2l + 2w

Substitute 2w with l in second equation to find l:
30 = 2l + 2w
30 = 2l + l
10 = l

Plug in 10 into first equation to find w:
l = 2w
10 = 2w
5 = w

4 0

4 years ago

In the figure M ab =45 and M cd= 23 what is the value of x?

const2013 [10]

Answer:

34°

Step-by-step explanation:

The measure of vertical angles formed by two chords is equal to one half the sum the measures of the arcs.

In other words, x is the average:

x = (23° + 45°) / 2

x = 34°

5 0

4 years ago

Find all solutions to the equation. -\dfrac{2}{x(x+2)}=\dfrac{x+3}{x+2}− x(x+2) 2 = x+2 x+3 minus, start fraction, 2, divide

Gnoma [55]

Answer:

$x=-1$

Step-by-step explanation:

We have been given an equation $\frac{-2}{x(x+2)}=\frac{x+3}{x+2}$ . We are asked to find the solutions of our given equation.

First of all, we will cross multiply our given equation as:

$-2(x+2)=x(x+2)(x+3)$

Subtract $x(x+2)(x+3)$ from both sides:

$-2(x+2)-x(x+2)(x+3)=x(x+2)(x+3)-x(x+2)(x+3)$

$-2(x+2)-x(x+2)(x+3)=0$

Now we will factor out $(x+2)$ .

$(x+2)(-2-x(x+3))=0$

$(x+2)(-2-x^2-3x)=0$

$(x+2)(-(x^2+3x+2))=0$

Now we will factor by splitting the middle term.

$-(x+2)(x^2+2x+x+2)=0$

$-(x+2)(x+2)(x+1)=0$

$-(x+2)^2(x+1)=0$

Now we will use zero product property and solve for x as:

$-(x+2)^2=0,(x+1)=0$

$(x+2)=0,(x+1)=0$

$x=-2,x=-1$

Now, we will check for extraneous solutions.

We can see that $x=-2$ will make both denominators zero because our function is not defined at $x=-2$ .

Therefore, the solution for our given equation is $x=-1$ .

7 0

4 years ago

Read 2 more answers

I NEED HELP ASAP!<br><br> 7x-3y= 6; х= 3

marysya [2.9K]

Answer:

If you are looking for y it's 5

Step-by-step explanation:

Plug in 3 for x

7(3) -3y = 6

21 - 3y = 6

subtract 21 from both sides

-3y = - 15

divide by three from both sides

y = 5

6 0

3 years ago

sally decided she wanted homework help. no one gave it to her. if over 100 people were on the app to help and 1 person helped ho

olga2289 [7]

Answer:

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3 years ago

Read 2 more answers