Question

An FM radio station broadcasts at 98 MHz. what is the energy of each photon in Joule? Use h= 6.6 X10^-34 J*s for Planck constant.

Answer 1

Answer:

The energy of each photon is $6.468 \times 10^{-26}$ Joule.

Step-by-step explanation:

Consider the provided information.

According to the plank equation:

$E=h\nu$

Where E is the energy of photon, h is the plank constant and $\nu$ is the frequency.

It is given that $h= 6.6 \times10^{-34}$ and $\nu=98MHz$

98Mhz = $98\times 10^6Hz$

Substitute the respective value in plank equation.

$E=6.6\times 10^{-34}\times 98\times 10^6$

$E=6.6\times 98\times 10^{-34+6}$

$E=646.8 \times10^{-28}$

$E=6.468 \times 10^{-26}$

Hence, the energy of each photon is $6.468 \times 10^{-26}$ Joule.