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alexandr402 [8]

3 years ago

12

A large container holds 5 gallons of water. it begins leaking at a constant rate. After 10 minutes the container has 3 gallons o

f water left. at what rate is the water leaking?

1 answer:

dolphi86 [110]3 years ago

7 0

First we have to find how much water leaked
5galllons-3 gallons=2 galllos of water leaked
Now we know $\frac{2 galllons}{10 minutes}$
Finally we can simplify it $\frac{2 gallons}{10 minutes}= \frac{1 gallon}{5 minutes}$ - its the answer

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13.El alquiler de un coche cuesta 20 € al día, más 0'50 € por kilómetro recorrido. Halla la ecuación que calcula lo que se cobra

Alchen [17]

Answer:

La función es: f(x) = 20+0.5x

Step-by-step explanation:

La función que representa la condición sería:

f(x) = 20+0.5x

Donde:

20 € es el costo por día
x es la cantidad de kilómetros
f(x) cobro por dia en función de los kilómetros

Espero te haya servido!

7 0

3 years ago

Will give brainly if right

garri49 [273]

Answer:

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8 0

2 years ago

PLEASE I NEED HELP INSTANTLY <br> I WILL GIVE BRAINLY AND THANKS

Goryan [66]

Answer:

so you're going to need to find the slope. in order to do that use (y2-y1)/(x2-x1)

(7-(-2))/(0-8)

simplify

9/-8

simplify -9/8

now using y=mx+b, we need to find b. so we can plug in the coordinates of (0,7) or (8,-2). let's use (8,-2) because it involves more math.

y=mx+b

-2=(-9/8)(8)+b

multiply (-9/8) by 8 to get -9

-2=-9+b

add 9 to both sides

7=b

so our equation is now

y=-(9/8)x+7

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Mine A is 225 feet underground and Mine B has an elevation of -223 feet. Which mine is further underground

LUCKY_DIMON [66]

Answer: Mine A

Step-by-step explanation: Mine A is further underground because elevation means height and when it’s shows a number that is negative that means underground. 225 is greater than 223. So Mine A is further underground.

3 0

3 years ago

Read 2 more answers

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

2 years ago