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miv72 [106K]
3 years ago
15

Which is not true of the weak nuclear force?

Physics
2 answers:
Sedbober [7]3 years ago
6 0

Answer: Option (A) is the correct answer.

Explanation:

A force that helps in binding protons and neutrons together in a nucleus is known as nuclear force. It is known that neutrons have no charge whereas protons have positive charge and like charges repel each other but due to the strong nuclear force which over powers the repulsion force between protons, they are held together in a nucleus.

A weak nuclear force is weaker than the strong nuclear force. Also, it acts over a shorter range than the strong nuclear force. A weak nuclear force is also attractive in nature.

But a weak nuclear force is not repellent in nature.

Thus, we can conclude that a weak nuclear force is a repellent force is not true.

Evgesh-ka [11]3 years ago
4 0
The answer is A. The weak nuclear force is usually an attractive force, and the other two answer choices are, indeed, true of the weak nuclear force.
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What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 22 km/h and the coef
Aleks [24]
First, let's put 22 km/h in m/s:

22 \frac{km}{h} \times  \frac{1000m}{1km}  \times  \frac{1h}{3600s}=6.11 \frac{m}{s}

Now the radial force required to keep an object of mass m, moving in circular motion around a radius R, is given by

F_{rad}=m \frac{v^2}{R}

The force of friction is given by the normal force (here, just the weight, mg) times the static coefficient of friction:

F_{fric}= mg \mu_{s}

Notice we don't use the kinetic coefficient even though the bike is moving.  This is because when the tires meet the road they are momentarily stationary with the road surface.  Otherwise the bike is skidding.

Now set these equal, since friction is the only thing providing the ability to accelerate (turn) without skidding off the road in a line tangent to the curve:

m\frac{v^2}{R} = mg \mu_{s} \\ \\ \frac{v^2}{R} = g \mu_{s} \\ \\R= \frac{v^2}{g \mu_{s}} \\ \\ R= \frac{6.11}{9.8 \times 0.37}=1.685m

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3 years ago
A generator produces 60 A of current at 120 V. The voltage is usually stepped up to 4500 V by a transformer and transmitted thro
aalyn [17]

Answer:

The percentage power lost in the transmission line if the voltage not stepped up is 50%.

Explanation:

Given that,

Current = 60 A

Voltage = 120 V

Resistance = 1.0 ohm

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Using formula of power

P=I\times V

Where,I =current

V = voltage

Put the value into the formula

P=60\times120

P=7200\ W

We need to calculate the percentage power lost in the transmission line

If the voltage is not stepped up

Then, the power loss

P'=I^2\times R

Put the value into the formula

P'=(60)^2\times1

P'=3600\ W

The percentage power loss P''

P''=\dfrac{P'}{P}\times100=\dfrac{3600}{7200}\times100

P''=50\%

Hence, The percentage power lost in the transmission line if the voltage not stepped up is 50%.

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