Which is not true of the weak nuclear force?

Physics

2 answers:

Sedbober [7]3 years ago

6 0

Answer: Option (A) is the correct answer.

Explanation:

A force that helps in binding protons and neutrons together in a nucleus is known as nuclear force. It is known that neutrons have no charge whereas protons have positive charge and like charges repel each other but due to the strong nuclear force which over powers the repulsion force between protons, they are held together in a nucleus.

A weak nuclear force is weaker than the strong nuclear force. Also, it acts over a shorter range than the strong nuclear force. A weak nuclear force is also attractive in nature.

But a weak nuclear force is not repellent in nature.

Thus, we can conclude that a weak nuclear force is a repellent force is not true.

Evgesh-ka [11]3 years ago

4 0

The answer is A. The weak nuclear force is usually an attractive force, and the other two answer choices are, indeed, true of the weak nuclear force.

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Sever21 [200]

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1 year ago

A charged particle having mass 6.64 x 10-27 kg (that of a helium atom) moving at 8.70 x 105 m/s perpendicular to a 1.30-T magnet

Fiesta28 [93]

Answer:

the charge of the particle is 2.47 x 10⁻¹⁹ C

Explanation:

Given;

mass of the particle, m = 6.64 x 10⁻²⁷ kg

velocity of the particle, v = 8.7 x 10⁵ m/s

strength of the magnetic field, B = 1.3 T

radius of the circle, r = 18 mm = 1.8 x 10⁻³ m

The magnetic force experienced by the charge is calculated as;

F = ma = qvB

where;

q is the charge of the particle

a is the acceleration of the charge in the circular path

$a = \frac{v^2}{r} \\\\ma = qvB\\\\q = \frac{ma}{vB} \\\\q = \frac{mv^2}{rvB} = \frac{mv}{rB} \\\\q = \frac{(6.64\times 10^{-27} ) \times (8.7\times 10^5)}{(1.8\times 10^{-2}) \times (1.3)} \\\\q = 2.47 \ \times 10^{-19} \ C$