1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OlgaM077 [116]
2 years ago
6

A converging lens of focal length 15cm is used to obtain a real image magnified 1½ times. calculate the distance of the image fr

om the lens
a. 37.5cm
b. 22.5cm
c.15.0cm
d.7.5cm
e.3.3cm​
Physics
1 answer:
Verdich [7]2 years ago
8 0

Answer:

don't know the answers sorry

You might be interested in
A child is playing on a swing. As long as he does not swing too high the time it takes him to complete one full oscillation will
Aleks [24]

Answer:

We know that for a pendulum of length L, the period  (time for a complete swing) is defined as:

T = 2*pi*√(L/g)

where:

pi = 3.14

L = length of the pendulum

g = gravitational acceleration = 9.8 m/s^2

Now, we can think on the swing as a pendulum, where the child is the mass of the pendulum.

Then the period is independent of:

The mass of the child

The initial angle

Where the restriction of not swing to high is because this model works for small angles, and when the swing is to high the problem becomes more complex.

7 0
3 years ago
The star Sirius has an apparent magnitude of -1.46 and appears 95-times brighter compared to the more distant star Tau Ceti, whi
dimaraw [331]

Answer:

(a) Apparent magnitude is the perceived brightness of an astronomical object

Absolute magnitude is the luminosity based on viewing an object from a 32.6 light-years distance

Bolometric magnitude is the total emitted radiation of a star

(b) The apparent magnitude of the star Tau Ceti = 3.51

(c) The distance between the Earth and Tau Ceti is 1.13 × 10¹⁴ km

Explanation:

(a) Apparent magnitude is an estimate of an astronomical objects' brightness as the object is perceived from the Earth

The absolute magnitude  is the magnitude an object appears to have when viewed from a 32.6 light-years distance while having constant transfer of its luminosity that is not affected by cosmic dust and objects present in the line of sight

The bolometric magnitude of a star is the sum total of the star's radiation released over all electromagnetic spectrum wavelengths

(b) The apparent magnitude of the star Tau Ceti is found using the following equation;

m_{2}-m_{1} = -2.512\times log\left (\dfrac{B_{2}}{B_{1}}  \right )

Where:

m₁ = Apparent magnitude of Tau Ceti

m₂ = Apparent magnitude of  Sirius = -1.46

B₁ = Brightness of Tau Ceti

B₂ = Brightness of Sirius

\left \dfrac{B_{2}}{B_{1}}  \right  = 95

Hence we have;

-1.46-m_{1} = -2.512\times log\left (95 \right )

m₁ = -1.46 + 2.512 × log(95) = 3.51

The apparent magnitude of the star Tau Ceti = 3.51

(c) The distance between the Earth and Tau Ceti is found using the following equation;

m-M = 5\times log\left (\dfrac{d}{10}  \right )

Where:

m = Apparent magnitude of Tau Ceti

M = Absolute magnitude of Tau Ceti = 5.69

d = The distance between the Earth and Tau Ceti

Which gives;

3.51-5.69 = 5\times log\left (\dfrac{d}{10}  \right )

\therefore \dfrac{d}{10} = 10^{-0.436} = 0.3664

d = 10 × 0.3664 = 3.664 parsecs = 3.664 × 3.0857 × 10¹⁶ m

d = 1.13 × 10¹⁴ km.

4 0
3 years ago
A 5000 kg train is traveling at a velocity of 100 m/s and hits another train. The two trains stick together and the new velocity
Nadya [2.5K]

Answer:

Explanation:

Conservation of momentum is used to solve

Unfortunately we have a missing piece of information such as the initial velocity of the unknown mass train.

If we ASSUME that the second train is at rest

5000(100) + m(0) = 5000(50) + m(50)

which means m = 5000 kg

However, I'll show you the importance of knowing that initial velocity by finding it assuming the other answers are valid

if m = 15000 kg

5000(100) + 15000(v₀) = (5000 + 15000)(50)

v₀ = 33 ⅓ m/s

if m = 10000 kg

5000(100) + 10000(v₀) = (5000 + 10000)(50)

v₀ = 25 m/s

if m = 8000 kg

5000(100) + 8000(v₀) = (5000 + 8000)(50)

v₀ = 18.75 m/s

So you can see why I had to assume an initial velocity. Any of the masses could work if the initial velocity is chosen correctly.

4 0
3 years ago
How are gravity and electromagnetic force similar and different?
oksano4ka [1.4K]

Answer:

The biggest difference is that gravity is an attractive force while electromagnetism is both an attractive and repelling force. Gravity happens between two objects depending on their masses, while electromagnetism is dependent on the objects' electric charges and the distance between them.

Explanation:

7 0
4 years ago
I need help plzzzzz!! ​
Vikki [24]

Explanation:

can u tell me which language is that

8 0
3 years ago
Other questions:
  • If June and Dylan do the same amount of work but June does it in 2.5 hours and Dylan in 3.2 hours who is more powerful?
    9·2 answers
  • In circular orbit, the gravitational force on a satellite is A. constant in magnitude. B. at right angles to satellite motion. C
    14·2 answers
  • An advantage of the clinical method is that is
    13·1 answer
  • A car initially traveling at 21.4 m/s accelerates at a rate of 4.4 m/s2 for 7.5 seconds. What is the final velocity of the car?
    6·1 answer
  • What is another name for the surface of the sun?
    14·1 answer
  • Which conditions must be met in order for work to be done?​
    15·1 answer
  • What is photoelectric effect​
    8·2 answers
  • Two objects are being lifted by a machine. One object has a mass of 2 kg, and is lifted at a speed of 2
    12·1 answer
  • [URGENT] A swimmer wants to end up at a dock due north of her starting position on the south shore of a river. In still water he
    10·1 answer
  • Question 8: Cosmology (8 points)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!