3 years ago

Help i need quick the test is today

Physics

2 answers:

alexdok [17]3 years ago

6 0

Answer:

As the mass increases the volume also increases

Explanation:

The graph is increasing so both must increase

tangare [24]3 years ago

4 0

Answer:

Mass and volume both increase

Explanation:

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Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resista

liraira [26]

Answer:

$\frac{dI}{dt} =-3*10^-^4amps/sec$

Explanation:

From the question we are told that

Voltage decreases at $\frac{dv}{dt} =-0.03volts/sec$

Resistance increase at $\frac{dR}{dt}=0.02ohms /sec$

Resistance at $R=100ohms$

Current at $I=0.02amps$

Generally the equation for ohms law is mathematically represented as

$V=IR$

Therefore

$\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}$

Generally making $\frac{dI}{dt}$ subject of the formula in the above equation mathematically gives

$\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}$

$R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}$

$\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})$

Therefore

$\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))$

Generally it is given that the change in current is

$\frac{dI}{dt} =-3*10^-^4amps/sec$

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