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DedPeter [7]
4 years ago
6

Organize the following expressions from greatest to least by number of terms:

Mathematics
2 answers:
pshichka [43]4 years ago
6 0

Answer:

2x^2y + x^2 - 3x + 4~ (4)>3x + y + z ~(3)>x + 2xyz ~(2)>9x^2yz~ (1)  

Step-by-step explanation:

We are given expressions in the question.

Term in an expression:

  • Each expression constitute terms.
  • A term can be a number, a variable, or a constant multiplied by a variable or variables.
  • Each term in an algebraic expression is separated by a + sign or - sign.

We need to find the number of terms in each expression:

1)

x + 2xyz\\\text{Number of terms}= 2

2)

3x + y + z\\\text{Number of terms}= 3

3)

2x^2y + x^2 - 3x + 4\\\text{Number of terms} = 4

4)

9x^2yz\\\text{Number of terms} = 1

Arranged  from greatest to least by number of terms:

2x^2y + x^2 - 3x + 4~ (4)>3x + y + z ~(3)>x + 2xyz ~(2)>9x^2yz~ (1)

AleksandrR [38]4 years ago
4 0
The order is III, II, I, IV
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An ellipse has vertices at (0, #17) and foci at (0, ±15). Write the equation of the ellipse in standard form. Graph the ellipse.
Lunna [17]

<u>ANSWER</u>

\frac{ {x}^{2} }{ 64 }  +  \frac{ {y}^{2} }{ 289 }  = 1

See attachment for the graph

<u>EXPLANATION</u>

The standard equation of the vertical ellipse with center at the origin is given by

\frac{ {x}^{2} }{ {b}^{2} }  +  \frac{ {y}^{2} }{ {a}^{2} }  = 1

where

{a}^{2}  \:  >  \:  {b}^{2}

The ellipse has its vertices at (0,±17).

This implies that:a=±17 or a²=289

The foci are located at (0,±15).

This implies that:c=±15 or c²=225

We use the following relation to find the value of b²

{a}^{2}  -  {b}^{2}  =  {c}^{2}

\implies \: 289  -  {b}^{2}  =  225

-  {b}^{2}  =  225 - 289

-  {b}^{2}  =  - 64

{b}^{2}  = 64

We substitute into the formula for the standard equation to get:

\frac{ {x}^{2} }{ 64 }  +  \frac{ {y}^{2} }{ 289 }  = 1

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