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VLD [36.1K]
3 years ago
11

itchell took a math exam today.If he got 63 out of 84 questions correct, what percentage did Mitchell get wrong?

Mathematics
2 answers:
shutvik [7]3 years ago
4 0

Answer: 25

Step-by-step explanation:

lorasvet [3.4K]3 years ago
4 0
Yeah answer I believe is 25
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What issue results from the combination of limited resources and unlimited wants?
melomori [17]
<span>The issue that results from the combination of limited resources and unlimited wants? is: Scarcity   </span>
5 0
3 years ago
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The second of two numbers is 8 less than twice the first number, what are the two numbers?
Mashutka [201]
So the two numbers can be represented as x and y

so x is first and y is second

y=2(x)-8

so y=2x-8


IF THEY ARE CONSECUTIVE
If they are consecutive numbers then 
x+1=y
subtitute
x+1=2x-8 
subtract x from both sides
1=x-8
add 8 to both sides and get
9=x
put it into the equation and get
y=2(9)-8
y=18-8
y=10
so x=9
y=10 
IF X AND Y ARE CONSECUTIVE INTEGERS (1,2,3,4 not 2.3 or 1,3,5,8)

3 0
4 years ago
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Please I need Steep by Steep Help 100 Points + Branly
mafiozo [28]

Answer:

a 4

b 3

c 9

d 4

Step-by-step explanation:

id.k

7 0
3 years ago
In scalene triangle abc, m∠b=45° and m∠c=55°. what is the order of the sides in length, from longest to shortest?
lubasha [3.4K]

The order of the sides of the triangle is bc>ab>ac as per the rule that side opposite to the larger angle is larger

8 0
4 years ago
Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0
cestrela7 [59]
When n=0, you have

4^0=1\equiv3(0)+1=1\mod9

Now assume this is true for n=k, i.e.

4^k\equiv3k+1\mod9

and under this hypothesis show that it's also true for n=k+1. You have

4^k\equiv3k+1\mod9
4\equiv4\mod9
\implies 4\times4^k\equiv4(3k+1)\mod9
\implies 4^{k+1}\equiv12k+4\mod9

In other words, there exists M such that

4^{k+1}=9M+12k+4

Rewriting, you have

4^{k+1}=9M+9k+3k+4
4^{k+1}=9(M+k)+3k+3+1
4^{k+1}=9(M+k)+3(k+1)+1

and this is equivalent to 3(k+1)+1 modulo 9, as desired.

3 0
4 years ago
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