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2 years ago

(4a) to the third power divided by (b-2) ; a=2 and b=4

Mathematics

1 answer:

Bingel [31]2 years ago

7 0

(4(2)=8*8*8=512÷6=85.333333
(4-2)=2
8-2=6
8*2=16
8÷2=4
8+2=10
whichever operation it is

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Solve for f is h=2f/m+1

Natasha_Volkova [10]

H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
<span>(the whole left side of the equation is divided by 2 i just cant do it on the computer)</span>

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3 years ago

The point (16, 12) lies on the terminal side of an angle. find cos, tan, and sin

frez [133]

The terminal side means that it's 16 to the right and 12 up. Which means that the triangle made from this has the sides of 16 and 12 and the hypotenuse is 20 units long. Theta, in this case, would have 16 as it's adjacent and 12 as it's opposite.
Therefore, using the Pythagorean identities:
<span> $sin(\theta) = \frac{12}{20} = \boxed{\frac{3}{5}} \\\ cos(\theta) = \frac{16}{20} = \boxed{\frac{4}{5}} \\\ tan(\theta) = \frac{12}{16} = \boxed{\frac{3}{4}}$ </span>

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3 years ago

HELPP ILL GIVE BRAINLESS

kobusy [5.1K]

15x=1000 you get x=1000/15 which is approximately 67

7 0

2 years ago

Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .

By definition, this procedure proves that $\lim_{x\to 5}f(x) = 14$ . Note that f(5)=14, so this proves that f is continous at x=5.

3 0

2 years ago

(50 POINTS) The figure is transformed as shown in the diagram. Describe the transformation. A) dilation, then reflection B) refl

Helga [31]

Answer:

Hi there I was just working on this question on UsaTestPrep and idk if the answer is really correct but here: C: reflection then rotation.

Step-by-step explanation:

Extra Info:

Dilation is when the shape changes in size, which doesn't happen.

Translation is when it just moves across. It may look like that is happening here, but I'll explain.

The triangle is first reflected along the line . Imaging putting a mirror on the x=0 line (the y axis, basically), and you'd see 1 to 2.

Then, it is rotated around the point . Get a bit of tracing paper, draw over 2, and then, holding the tracing paper down at (works well with a pencil), rotate it round and you will find it fits perfectly over 3.

Also is this the diagram?

6 0

2 years ago