<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7Dn-18%3D%5Cfrac%7B1%7D%7B4%7D%20n-4" id="TexFormula1" title="\frac{3}{4}n-

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lbvjy [14]

3 years ago

18=\frac{1}{4} n-4" alt="\frac{3}{4}n-18=\frac{1}{4} n-4" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

umka2103 [35]3 years ago

8 0

The value of n is $n=28$

Explanation:

The expression is $\frac{3}{4} n-18=\frac{1}{4} n-4$

Subtracting both sides by $\frac{1}{4} n$ , we get,

$\frac{3}{4}n-\frac{1}{4}n-18=-4$

Adding both sides by 18, we get,

$\frac{3}{4}n-\frac{1}{4}n=-4+18$

Simplifying the terms, we have,

$\frac{2}{4}n=14$

Dividing, we get,

$\frac{1}{2} n=14$

Multiplying by 2, we have,

$n=28$

Thus, the value of n is $n=28$

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Use the discriminant to determine how many real number solutions exist for the quadratic equations -4j+3j-28=0

aleksandr82 [10.1K]

<span>the correct equation is
- 4j² + 3j - 28 =0

ax² + bx + c,
a = -4, b=3 c =- 28.
The discriminent D = b² - 4.a.cD = 3² - 4(-4)(-28)D = -439
If D ≥ 0 there are either 2 roots or one double if = 0)if D< 0, there are no real roots (but 2 imaginary roots)Since D < 0, then there is no real roots
The answer there is no real roots</span>

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Answer:

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 250, \sigma = 75$

If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?

What is the percentile of 350?

This is the pvalue of Z when X = 350.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{250 - 150}{75}$

$Z = 1.33$

$Z = 1.33$ has a pvalue of 0.9082.

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

If not, what number of shelter openings will be needed?

The 95th percentile, which is X when Z = 1.645. So

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$1.645 = \frac{X - 150}{75}$

$X - 150 = 1.645*75$

$X = 274$

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