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VARVARA [1.3K]
3 years ago
5

A 0.5-kg ball accelerated at 50 m/s2 . What force was applied?

Physics
2 answers:
Lapatulllka [165]3 years ago
5 0

Answer:

The answer is Force is equal to 25N

Explanation:

1) Taking into account Newton's second law, which expresses that the acceleration that a body acquires is directly proportional to that resulting from the forces acting on it, and has the same direction as that resulting.

2) This law is expressed with the formula F = ma where (F) represents force, (m) represents mass and (a) represents acceleration.

3) knowing this we can replace the values given in the problem and solve:

F = (0,5kg)(50m/s^2)

F = 25N

Alex_Xolod [135]3 years ago
4 0
The answer will be 25n because force equals mass times acceleration

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This is a computer program, why is there an error between the computer values and the nominal values of R?
ss7ja [257]

Answer:

the difference is due to resistance tolerance

Explanation:

In mathematical calculations, either done by hand or in a computer program, the heat taken from the resistors is the nominal value, which is the writing in its color code, so all calculations give a result, but the Resistors have a tolerance, indicated by the last band that is generally 5%, 10%, 20% and in the expensive precision resistance can reach 1%.

   This tolerance or fluctuation in the resistance value is what gives rise to the difference between the computation values ​​and the values ​​measured with the instruments, multimeters.

   Another source of error also occurs due to temperature changes in the circuit that affect the nominal resistance value, there is a very high resistance group that indicates the variation with the temperature, they are only used in critical circuits, due to their high cost

In summary, the difference is due to resistance tolerance.

5 0
4 years ago
A baseball travels 50 meters in 4 seconds what is the average velocity of the baseball?
beks73 [17]
The average velocity is 12.5 meters per second
5 0
3 years ago
Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r
Zepler [3.9K]

Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example

answer : a) 14 ohms  b) 0.86 amps   c) 10.32 V

Explanation:

Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms

Voltage source = 12V

<u>Assuming that the Resistors are in series </u>

<u>a) Determine Total resistance </u>

Req = R1 + R2 + R3

       = 3 + 4 + 5 = 14 ohms

<u>b) Total current </u>

Ieq = V / Req

      = 12 / 14 =  0.86 amps

<u>c) The Total Voltage over the entire system </u>

Vt = ∑ Voltage drops

    = ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )

    = 10.32 V

5 0
3 years ago
Doe the baby diaper tabs go to the front or back. Huggies diaper.
Zielflug [23.3K]

Answer:

back lol

Explanation:

Pull the tabs and wrap around to stick to the front of the diaper:)

3 0
4 years ago
Read 2 more answers
Consider n equal positively charged particles each of magnitude Q/n placed symmetrically around a circle of radius a. Calculate
Sonja [21]

Answer: Magnitude of electric field =p × Ke × Q/d^3

Explanation: Using Coulombs law of point charge,each charge on the circle would exert a fieldEc at point given by:

Ec= Ke × (Q/n)/d^2

Where Ke= Coulomb's constant

d= distance between the charges and the point of measurement, P with d^2=a^2+p^2

(Q/n)= Magnitude of the charge.

For charges in a circle,all the force components and direction(x,z) are cancelled by the symmetry,leaving only the vertical force(y-direction)

The Resultant vector will be

Ecy=Eq × sin(theta)

Ecy=Ke × (Q/n)/d^2 ×(p/d)

Adding the forces from all the charges,the magnitude of electric field Ey=n×Ecy

/Ey/= n ×[Ke ×(Q/n)/d^2 ×(p/d)]

/Ey/= p × Ke × (Q/d^3)

3 0
3 years ago
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