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3 years ago

7

An artificial satellite orbits Earth at a speed of 7800 m/s and a height of 200 km above Earth’s surface. The satellite experien

ces an acceleration due to gravity of
A39 m/s2
Bless than 39 m/s2 but greater than 9.8 m/s2
C9.8 m/s2
Dless than 9.8 m/s2 but greater than zero

1 answer:

stepladder [879]3 years ago

8 0

Answer: less than 9.8 m/s^2 but greater then zero

Explanation:

Gravitation law

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3 years ago

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Two concrete spans of a 380 m long bridge are

Mazyrski [523]

Answer:

4.163 m

Explanation:

Since the length of the bridge is

L = 380 m

And the bridge consists of 2 spans, the initial length of each span is

$L_i = \frac{L}{2}=\frac{380}{2}=190 m$

Due to the increase in temperature, the length of each span increases according to:

$L_f = L_i(1+ \alpha \Delta T)$

where

$L_i = 190 m$ is the initial length of one span

$\alpha =1.2\cdot 10^{-5} ^{\circ}C^{-1}$ is the temperature coefficient of thermal expansion

$\Delta T=20^{\circ}C$ is the increase in temperature

Substituting,

$L_f=(190)(1+(1.2\cdot 10^{-5})(20))=190.0456 m$

By using Pythagorean's theorem, we can find by how much the height of each span rises due to this thermal expansion (in fact, the new length corresponds to the hypothenuse of a right triangle, in which the base is the original length of the spand, and the rise in heigth is the other side); so we find:

$h=\sqrt{L_f^2-L_i^2}=\sqrt{(190.0456)^2-(190)^2}=4.163 m$

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3 years ago

1. Una pelota rueda hacia la derecha siguiendo una trayectoria en línea recta de modo que recorre una distancia de 10m en 5 s ,

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3 years ago

How long does it take (in minutes) for light to reach venus from the sun, a distance of 1.152 × 108 km?

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Using the precise speed of light in a vacuum ( $299,792,458 \ \frac{m}{s}$ ), and your given distance of $1.152 * 10^{8} km$ , we can convert and cancel units to find the answer. The distance in m, using $\frac{1000 \ m}{1 \ km}$ , is $1.152 * 10^{11} m$ . Next, for the speed of light, we convert from s to min, using $\frac{1 \ min}{60 \ s}$ , so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is 6.405 min.

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3 years ago