∆g for these initial partial pressures is 10,403.31 KJ.
ΔG gets increasingly positive as a product gas's partial pressure is raised. ΔG becomes more negative as the partial pressure of a reactant gas increases.
∆g = RT ln (q/k)
In this equation: R = 8.314 J mol⁻¹ K⁻¹ or 0.008314 kJ mol⁻¹ K⁻¹
K = 325
If ΔG < 0, then K > Q, and the reaction must proceed to the right to reach equilibrium.
∴∆g = RT ln (q/k)
= 8.314 × 298 ln ( 5 / 325)
= 2477.57 ln 0.015
= 2477.57 × (-4.199)
= 10,403.31 KJ
Products are preferred over reactants at equilibrium if G° 0 and both the products and reactants are in their standard states. When reactants are preferred above products in equilibrium, however, if G° > 0, K 1. At equilibrium, neither reactants nor products are preferred if G° = 0, hence K = 1.
Therefore, ∆g for these initial partial pressures is 10,403.31 KJ.
Learn more about equilibrium here:
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I’m guessing is because she uses force to throw the ball, allowing the energy to move the person.
sorry if it’s not 100% correct
If the coefficient of static friction is 0.3, then the minimum force required to get it moving is equal in magnitude to the maximum static friction that can hold the body in place.
By Newton's second law,
• the net vertical force is 0, since the body doesn't move up or down, and in particular
∑ <em>F</em> = <em>n</em> - <em>mg</em> = <em>n</em> - 50 N = 0 ==> <em>n</em> = 50 N
where <em>n</em> is the magnitude of the normal force; and
• the net horizontal force is also 0, since static friction keeps the body from moving, with
∑ <em>F</em> = <em>F'</em> - <em>f</em> = <em>F'</em> - <em>µn</em> = <em>F'</em> - 0.3 (50 N) = 0 ==> <em>F'</em> = 15 N
where <em>F'</em> is the magnitude of the applied force, <em>f</em> is the magnitude of static friction, and <em>µ</em> is the friction coefficient.
Answer:
7500 m
Explanation:
The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.
We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so
d = 2L
In a time of
Electromagnetic waves travel in a vacuum at the speed of light, which is equal to
Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:
(1)
where
, where L is the distance between the radar and the object
Re-arranging eq(1) and substituting, we find L:
Answer:
f(-9) = 184
Explanation:
f(x)=3x²+5x-14
f(-9)= 3(-9)² +5(-9)-14 Order of Operations : Exponents
= 3(81)+5(-9)-14
= 243+5(-9)-14
= 243-45-14
= 198-14
f(-9)= 184
Hope this helps :)
