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trapecia [35]
3 years ago
5

Three points, A, B, and C exists in space such that B is "between" A and C. It is known that AB=7, BC=4, and AC=9. Are points A,

B, and C collinear? Give a written explanation, supported by mathematical evidence, for your answer.
Mathematics
2 answers:
sergeinik [125]3 years ago
7 0
If the points are collinear, then that means they lie on the same line when connected to each other. In order to prove this, the distances between the points must sum up to the length of the line.

AB + BC = AC
7 + 4 ? 9
11 ≠ 9

Since they do not sum up, therefore, the points are not collinear.
garri49 [273]3 years ago
7 0
Collinear means they lie on the same line when connected to each other. In order for you to prove this, the distances between the points have to add up to the length of the line.

AB + BC = AC

7 + 4 ? 9

11 ≠ 9

<span>So since they don't add up, the points are not collinear.</span>
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2 years ago
How do I solve this?
bogdanovich [222]

Answer:

<h2>5(x + 7)²</h2>

Step-by-step explanation:

5(x+7)^4=\boxed5\cdot\boxed{(x+7)}\cdot\boxed{(x+7)}\cdot(x+7)\cdot(x+7)\\\\35(x+7)^2=\boxed5\cdot7\cdot\boxed{(x+7)}\cdot\boxed{(x+7)}\\\\15(x+7)^3=\boxed5\cdot3\cdot\boxed{(x+7)}\cdot\boxed{(x+7)}\cdot(x+7)\\\\GCF\bigg(5(x+7)^4,\ 35(x+t)^2,\ 15(x+7)^3\bigg)=\boxed5\cdot\boxed{(x+7)}\cdot\boxed{(x+7)}\\\\=5(x+7)^2

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3 years ago
The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co
julia-pushkina [17]

Answer:

P[X=3,Y=3] = 0.0416

Step-by-step explanation:

Solution:

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                        P[X=3,Y=3] = P[X=3]*(P[C=1]^3) = 0.25*(0.55)^3

                        P[X=3,Y=3] = 0.0416

6 0
2 years ago
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