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trapecia [35]
3 years ago
5

Three points, A, B, and C exists in space such that B is "between" A and C. It is known that AB=7, BC=4, and AC=9. Are points A,

B, and C collinear? Give a written explanation, supported by mathematical evidence, for your answer.
Mathematics
2 answers:
sergeinik [125]3 years ago
7 0
If the points are collinear, then that means they lie on the same line when connected to each other. In order to prove this, the distances between the points must sum up to the length of the line.

AB + BC = AC
7 + 4 ? 9
11 ≠ 9

Since they do not sum up, therefore, the points are not collinear.
garri49 [273]3 years ago
7 0
Collinear means they lie on the same line when connected to each other. In order for you to prove this, the distances between the points have to add up to the length of the line.

AB + BC = AC

7 + 4 ? 9

11 ≠ 9

<span>So since they don't add up, the points are not collinear.</span>
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The number sentence 4x6=6x4 is an example of the what property
monitta

Answer:

commutative property of multiplication

Step-by-step explanation:

The value of the product of the given equation remain the same while the order is reversed

The number sequence 4 × 6 = 6 × 4 is an example of the commutative property of multiplication

Reason:

The given number sentence is 4 × 6 = 6 × 4

Required: The property the number sentence is an example of (represent)

Solution:

The difference between the left and right expression is that the order of the

values being multiplied is changed or reversed (commute)

Therefore, the number sentence states that the value of the multiplication

of two variables remain equal when the places of variables are

interchanged as follows; a × b = b × a

a × b = b × a is an example of commutative property of multiplication

Therefore;

4 × 6 = 6 × 4 is an example of the commutative property of multiplication

5 0
3 years ago
Somebody please help me
WITCHER [35]

Step-by-step explanation:

x - 1 = - 3x - 14

Bringing like terms on one side

x + 3x = -14 + 1

4x = - 13

x = - 13/4

5 0
3 years ago
The scientist performs additional analyses and observes that the number of major earthquakes does appear to be decreasing but wo
kifflom [539]

Answer:

Step-by-step explanation:

Hello!

A regression model was determined in order to predict the number of earthquakes above magnitude 7.0 regarding the year.

^Y= 164.67 - 0.07Xi

Y: earthquake above magnitude 7.0

X: year

The researcher wants to test the claim that the regression is statistically significant, i.e. if the year is a good predictor of the number of earthquakes with magnitude above 7.0 If he is correct, you'd expect the slope to be different from zero: β ≠ 0, if the claim is not correct, then the slope will be equal to zero: β = 0

The hypotheses are:

H₀: β = 0

H₁: β ≠ 0

α: 0.05

The statistic for this test is a student's t: t= \frac{b - \beta }{Sb} ~~t_{n-2}

The calculated value is in the regression output t_{H_0}= -3.82

This test is two-tailed, meaning that the rejection region is divided in two and you'll reject the null hypothesis to small values of t or to high values of t, the p-value for this test will also be divided in two.

The p-value is the probability of obtaining a value as extreme as the one calculated under the null hypothesis:

p-value: P(t_{n-2}\leq -3.82) + P(t_{n-2}\geq  3.82)

As you can see to calculate it you need the information of the sample size to determine the degrees of freedom of the distribution.

If you want to use the rejection region approach, the sample size is also needed to determine the critical values.

But since this test is two tailed at α: 0.05 and there was a confidence interval with confidence level 0.95 (which is complementary to the level of significance) you can use it to decide whether to reject the null hypothesis.

Using the CI, the decision rule is as follows:

If the CI includes the "zero", do not reject the null hypothesis.

If the CI doesn't include the "zero", reject the null hypothesis.

The calculated interval for the slope is: [-0.11; -0.04]

As you can see, both limits of the interval are negative and do not include the zero, so the decision is to reject the null hypothesis.

At a 5% significance level, you can conclude that the relationship between the year and the number of earthquakes above magnitude 7.0 is statistically significant.

I hope this helps!

(full output in attachment)

5 0
3 years ago
********PLEASE HELP ****** DVD players are going out of fashion in the modern era. If 400,000 DVD players were sold this year an
abruzzese [7]
So 400,000 DVD sales with a 31% decline means in the 1st year following, there will be a decline of 124,000 DVDs sold. So we need to take 400,000 - 124,000, which equals a starting point for year two is 276,000 DVDs.

So a 31% decline on 276,000 = 85,560. So we need to subtract that from 85,560 from 276,000 which is 190,440. So at the end of the second year, DVD sales were only 190,440.  That's also out starting point of the 3rd year. 

So 31% of 190,440 equals 59,036.4 for the third year of DVD sales. So we need to subtract 59,036.4 from out third year starting point of 190,440, which equals 131,403.6, but since you can't have parts of DVDs, we'll round the decimal point fraction to a whole number to end up with 131,404 DVDs sold in year three.

So after three years of a 31% yearly decline in DVD sales you end up with DVD sales are 131,404














3 0
3 years ago
Read 2 more answers
1. What is the simple interest on $4,500 for 2 and a half years at 4% per year?
allochka39001 [22]

Answer: 1st is 180$ sorry if I’m wrong

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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