Question

Jessica had a bag of candies. She gave 1/8 of her candies to judy. Then jessica gave 3/7 of the candies she had left to Reggie. Then she lost 75% of what she had left. After all this, Jessica only had 4 candies left. How many candies did Jessica have at the beginning? Pls help

Answer 1

Answer:

Jessica had 32 candies at the beginning.

Step-by-step explanation:

Let the number of candies Jessica had at the beginning be $x$.

Candies gives to Judy = $\frac{1}{8}x$.

Now, candies left with Jessica is $x-\frac{1}{8}x=\frac{7x}{8}$.

Candies given to Reggie is $\frac{3}{7}$ of $\frac{7x}{8}$.

∴ Candies with Reggie is $\frac{3}{7}\times\frac{7x}{8}=\frac{3x}{8}$.

Candies left with Jessica after giving to Reggie = $\frac{7x}{8}-\frac{3x}{8}=\frac{4x}{8}$.

Now, Jessica lost 75% of what she had left. So, 75% of $\frac{4x}{8}$.

∴ Candies lost = $\frac{75}{100}\times\frac{4x}{8}= \frac{3x}{8}$

Now, candies left with Jessica = $\frac{4x}{8}-\frac{3x}{8}=\frac{x}{8}$.

As per question,

Candies left with Jessica at last is 4. So,

$\frac{x}{8}=4$

$x=32$

Hence, Jessica had 32 candies at the beginning.