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makvit [3.9K]
3 years ago
7

Ashley has two jobs: mowing lawns and babysitting. She earns $9 per hour mowing lawns (x) and $7 per hour babysitting (y). She a

lso wants to earn at least $147 per week. Write an inequality in standard form to describe all possible combinations to the limitation above
Mathematics
2 answers:
scZoUnD [109]3 years ago
8 0

Answer:

Troolllllllllllllll

Step-by-step explanation:

ttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrroooooooooooooooooooooooooooooooooooooooooooooooooooooooooooollllllllllllllllllllllllllllllllllllllllllllllllllllllllll

 

The Punnett square above shows a cross between two sweet pea plants in Mendel's greenhouse. Both parents have blue flowers (Bb).

Which statement describes the offspring expected from this cross?

A) 50% white-flowered and 50% blue-flowered  

B) 75% white-flowered and 25% blue-flowered  

C) 75% blue-flowered and 25% white-flowered  

D) 100% blue-flowered and 0% white-flowered

SpyIntel [72]3 years ago
6 0

Answer:

The correct answer is 9x + 7 y \geq 147 where Ashley works for x hours as lawn mower and y hours as babysitter per week.

Step-by-step explanation:

Ashley works in two different jobs namely mowing lawns and babysitting.

Let Ashley mow lawn for x hours and babysit for y hours in a week.

Ashley's earning for every hour she mow is $ 9. Total earning mowing lawn is $ 9x.

Ashley earns $7 for every hour she babysit. Total earning babysitting is $ 7y.

Total earning per week $ (9x + 7y).

Ashley's earning per week is at least $147.

∴ The required inequality to describe the above case is 9x + 7 y \geq 147.

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A solution to a system of linear equations in two variables is an ordered pair that
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Answer:

satisfies both equations in the system.

Step-by-step explanation:

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A solution to a system of linear equations in two variables is an ordered pair that

6 0
3 years ago
Use the equation of the water level of the river represented by the equation y=-4x + 170, where x represents the
vovangra [49]

Answer:

(0,170)  and (60,-70) and (5, 150)

Step-by-step explanation:

To see if a given point is on the line or not, you just have to enter the x value (first value in the parenthesis) and see if the function returns the correct y value (second number in the parenthesis).

f(x) = -4x + 170

(170,0)  => -4 (170) + 170 = -680 + 170 = 510.  NO, not equal to 0.

(0,170) =>  -4 (0) + 170 = 0 + 170 = 170. YES

(12, 126)  => -4 (12) + 170= -48 + 170= 122. No, not equal to 126.

(50,30)  => -4(50) + 170 = -200 + 170 = 130. No, not equal to 30.

(5, 150)  => -4(5) + 170 = -20 + 170 = 150. YES

(60,-70) => -4(60) + 170 = -240 + 170 = -70.  YES

4 0
3 years ago
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julio plans to spend 2 3/4 hours studying for an upcoming test. If he spends 1 1/4 hours studying on tuesday how many hours shou
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6 0
3 years ago
How many tickets were sold after June 15th?
AysviL [449]

Answer: About 45.

Step-by-step explanation: There's always a pattern in these kinds of questions, you can see for 9th to 13th August, the number has always been  between 20 to 40. And since on 13th August the graph is on a rise again, it would be around 45. 90 is just not realistic considering there's only an increase of around 5-10 tickets every day.  

8 0
3 years ago
Three people invest in a treasure dive, each investing the amount listed below. The dive results in 40 gold coins. Apportion tho
garri49 [273]

Answer:

Alice: 20 coins, Ben: 16 coins, and Carlos: 4 coins.

Step-by-step explanation:

We know that the dive results in 40 gold coins.

We know that:

Alice: $7,600 Ben: $5,900 Carlos: $1,400.

So they have $ 14900 in total.

Now we will divide that money by 40.

x=\frac{14900}{40}\\\\x=372.5

So 1 gold coin costs $ 372.5. Now we will calculate how much they can get for the money they have.

A=\frac{7600}{372.5}=20.4\\\\B=\frac{5900}{372.5}=15.8\\\\C=\frac{1400}{372.5}=3.75\\

We conclude that:

Alice: 20 coins, Ben: 16 coins, and Carlos: 4 coins.

6 0
3 years ago
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