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lora16 [44]
3 years ago
5

The point (−7, -24) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent o

f θ? Make sure to show all work.
Mathematics
1 answer:
babymother [125]3 years ago
4 0

Answer:

\sin 253.740^{\textdegree} = -\frac{24}{25} = -0.960

\cos 253.740^{\textdegree} = -\frac{7}{25} = -0.280

\tan 253.340^{\textdegree} = \frac{24}{7} =  3.429

Step-by-step explanation:

The point is in the 3rd Quadrant of the Cartesian Plane. Therefore, angle must be between 180° and 270° with respect to the horizontal.

The angle is:

\theta = 180^{\textdegree}+\tan^{-1}\left(\frac{24}{7} \right)

\theta \approx 253.740^{\textdegree}

The values of the trigonometrical functions are computed below:

\sin 253.740^{\textdegree} = -\frac{24}{25} = -0.960

\cos 253.740^{\textdegree} = -\frac{7}{25} = -0.280

\tan 253.340^{\textdegree} = \frac{24}{7} =  3.429

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