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Hoochie [10]
3 years ago
9

Find xA) 12B) 13 C) 11D) 10

Mathematics
1 answer:
Soloha48 [4]3 years ago
5 0

We know that the sum of arc ND and arc ML divided by 2 is equivalent to 6x + 23.

Thus, we can form an equation:

6x + 23 = (11x + 8 + 3x + 14)/2

Simplify:

6x + 23 = (14x + 22)/2

Simply again:

6x + 23 = 7x + 11

Subtract 6x from both sides:

23 = x + 11

Subtract 11 from both sides

x = 12

Option A, or x = 12

-T.B.

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What polynomial identity should be used to prove that 35 = 8 + 27
Julli [10]

Answer:

Sum of cubes identity should be used to prove 35 =3+27

Step-by-step explanation:

Prove that : 35 = 8 +27

Polynomial identities are just equations that are true, but identities are particularly useful for showing the relationship between two apparently unrelated expressions.

Sum of the cubes identity:

a^3+b^3=(a+b)(a^2-ab+b^2)

Take RHS

8+ 27

We can write 8 as 2 \times 2 \times 2 = 2^3 and 27 as 3 \times 3 \times 3 = 3^3.

then;

8+27 = 2^3+3^3

Now, use the sum of cubes identity;

here a =2 and b = 3

2^3+3^3 = (2+3)(2^2-2\cdot 3+3^2)

or

2^3+3^3 = (5)(4-6+9) = 5 \cdot 7 = 35 = LHS    proved!

therefore, the Sum of cubes polynomial identity should be used to prove that 35 = 8 +27

4 0
3 years ago
Read 2 more answers
What is (2n+2n)-(3n-4n)
Yakvenalex [24]

Answer:

2n^{2} +2n

INSERT

Step-by-step explanation:first you want to move the negative which is negative 1 into the set of parenthesis and then Foil the two parenthesis together and the combine like terms

7 0
3 years ago
8,264 is divisible by 3? True or false?
mars1129 [50]
Number\ is\ divisible\ by\ 3\ if\ the\ sum\ of\ the\ digits\ is\ divisible\ by\ 3.\\\\8,264\\\\8+2+6+4=20-
is\ not\ divisible\ by\ 3.\\\\8,264\ is\ divisible\ by\ 3-FALSE
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3 years ago
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lesantik [10]
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4 0
3 years ago
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You have total coins for a total of $. . You only have quarters and dimes. Let represent the number of quarters and represent th
Sonja [21]

Answer:

Quarters = 41

Dimes = 18

Step-by-step explanation:

Given

Coins = 59

Worth = \$12.05

d = dimes

q = quarters

Required

The number of each coin

The total coins can be represented as:

d + q = 59

1\ quarter = \$0.25 \\ 1\ dime = \$0.10

So, the worth of the coin is:

0.25q + 0.10d = 12.05

The equations to solve are:

0.25q + 0.10d = 12.05

d + q = 59

Make d the subject in: d + q = 59

d =59 - q

Substitute d =59 - q in 0.25q + 0.10d = 12.05

0.25q + 0.10(59 - q) = 12.05

0.25q + 5.9 - 0.10q = 12.05

Collect like terms

0.25q  - 0.10q = 12.05 - 5.9

0.15q = 6.15

Solve for q

q=\frac{6.15}{0.15}

q=41

Substitute q=41 in d =59 - q

d = 59 - 41

d = 18

So:

Quarters = 41

Dimes = 18

5 0
3 years ago
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