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For this case we have the following system of equations:

Equating both equations we have:

We must find the solutions, for this we factor. We look for two numbers that, when multiplied, result in 4 and when added, result in 5. These numbers are 4 and 1:

Then, the factorized equation is of the form:

Thus, the solutions are:

We look for solutions for the variable "y":

Thus, the system solutions are given by:
ANswer:

1st statement: x+4=x/2+10
2nd statement: x^2 +6=2x+9