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Andreas93 [3]
3 years ago
6

How do I work this problem out.

Mathematics
2 answers:
astraxan [27]3 years ago
7 0
First you should find the area of the rectangle in the middle.
A: 9 x 6 = 54
Then you can find the area of the triangle on the right.
A: 6 x 5 = 30/2 = 15
Then you can do the triangle on the right.
11-9 = 2
A: 2 x 6 = 12/2 = 6
Then you can add it all together.
15 + 6 + 54 = 74
So the area of the irregular shape is 74.

I hope this helps!
kompoz [17]3 years ago
4 0
Well i would look at the trapezium on the left (i would forget the first dashed line) and use 1/2 a + b × h to work out the area of a trapezium. So you would do 1/2 of 9+11 × 6 which is 60cm^2.
Then I would work out the area of the triangle which is 1/2 b×h. You would do 1/2 of 6×5 which is 15cm^2.
Add 60 and 15 and you get 75cm^2
Ok looking at the other persons I think I did it wrong
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