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Arte-miy333 [17]
3 years ago
15

Five times the sum of a number and 27 is greater than or equal to six times the sum of that num

Mathematics
1 answer:
stepladder [879]3 years ago
7 0

Question:

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.

What is the solution set of this problem?

Answer:

x \leq -21

Step-by-step explanation:

Given

<em>Represent the number with x</em>

So:

5 * (x + 27) \geq 6 * (x + 26)

Required

Determine the solution set

5 * (x + 27) \geq 6 * (x + 26)

Open Both Brackets

5 * x + 5 * 27 \geq 6 *x + 6 * 26

5x + 135 \geq 6x + 156

Collect Like Terms

5x - 6x \geq 156-135

- x \geq 21

Multiply both sides by -1

x \leq -21

Hence, the solution set is x \leq -21

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Answer:

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Step-by-step explanation:

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MAXImum [283]

Answer:

<h2>a-b = 156π</h2>

Step-by-step explanation:

<u>For the inscribed circle</u>

Formula for calculating the radius of an inscribed circle in a triangle r = Area of the triangle/0.5 of its perimeter

Given a triangle of side 10, 24 and 26.

Area of the triangle = 1/2 * base * height

Area of the triangle = 1/2*10*24

Area of the triangle = 120

Perimeter of the triangle = 10+24+26 = 60

radius of the inscribed circle = 120/0.5(60)

r = 120/30

r = 4

Area of the incircle b = πr² = π(4)² = 16π

<u>For the circumcircle</u>

Formula for calculating the radius of a circumcircle outside a triangle

R = abc/4√s(s-a)(s-b)(s-c)

s = a+b+c/2

a, b and c are the length of the 3 sides

s = 10+24+26/2

s = 60/2 = 30

R = 10(24)(26)/4√30(20)(6)(4)

R = 6240/4*120

R = 13

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4 years ago
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Answer:

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Step-by-step explanation:

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