Convert the rate of 24 in/sec to an equivalent rate measured in ft/sec

Juan put three square tiles with sides 8 centimeters, 10 centimeters, and x centimeters together so that they form a right trian

Elan Coil [88]

Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to $x^{2}$ .
$A = x^{2}$ ---> equation (1)
By using pythagoras rule which states that the $x^{2} = hyp^2 - opposite^2$ ---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
$x^{2} = 10^{2} - 8^{2}$ substitute this value in equation (1) then
$A = x^{2} = 10^{2} -8^{2}$
where A is the area of the square whose side is x

6 0

2 years ago

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____ more than 3455 is two hundred seventy -eight thousand five hundred eighty three

Pavlova-9 [17]

278, 538 is the answer

3 0

3 years ago

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Please answer correctly will mark brainliest and will follow

Schach [20]

9514 1404 393

Answer:

q/2, p, q

Step-by-step explanation:

You know the area of a triangle is half the product of base and height. The two triangles of interest here have base length p and height q/2. You're being asked to fill in the missing base or height dimension.

$=\dfrac{1}{2}\times p \times\boxed{\dfrac{q}{2}}+\dfrac{1}{2}\times\boxed{p}\times\dfrac{q}{2}\\\\=\dfrac{1}{2}\times p\times\boxed{q}$

5 0

3 years ago

Graph the systems of equations.<br><br> {2x+y=8−x+2y=6

victus00 [196]

Hi, I actually just took the test and got 100%

Remember: When plotting the points for this equation, make sure to always first plot the ones that correspond to the first linear equation, and then plot the ones that correspond to the second linear equation.

The points on the line should be for the first linear equation, (4,0) and (8,0). I got this answer by first converting the linear equation, 2x+y=8 from standard form to slope-intercept form. To do this, I subtracted 2x from both sides of the equation. So now it reads as y=8-2x. After this step was completed, I then graphed my first linear equation.
The points on the line should be for the first linear equation, (2,4) and (6,6).
I got this answer by first converting the linear equation, -x+2y=6 into slope-intercept form. To do this, I subtracted -x from both sides of the equation. Then I had to divide the 2 into both -x and 6. So now it reads as y= 6/2-x/2. After this step was completed, I then graphed my second and final linear equation.

I hope this helps!

5 0

3 years ago

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(2k 3 +6k+1)−(2k 2 +1). Simplify and put into standard form

Rzqust [24]

Answer:

$2k^3-2k^2+6k$ .

Step-by-step explanation:

We have been given an expression and we are asked to simplify our given expression.

$(2k^3+6k+1)-(2k^2+1)$

Using order of operations (PEMDAS) we will remove parenthesis first.

After removing parenthesis our expression will be,

$2k^3+6k+1-2k^2-1$

After canceling out 1 with -1 we will get,

$2k^3+6k-2k^2$

So our given expression simplifies to $2k^3+6k-2k^2$ .

Let us write our expression in standard form. Since our expression is a polynomial and to write any polynomial in standard form, we write each term in order of degree, from highest to lowest, left to right.

Upon putting our polynomial into standard form we will get,

$2k^3-2k^2+6k$

Therefore, after simplifying and putting our given expression in standard form we get our final expression as: $2k^3-2k^2+6k$ .

6 0

3 years ago