No, if x=1 then you get an undefined statement
if you want to try to simplify then
x^2-3x+2=(x-1)(x-2)
((x-1)(x-2))/(x-1)=x-2 is that true?
x-1 cancels out
x-2=x-2
true
but, the x-1 is trickey
if x=1, then the denomenator becomes 0 and the equation is undefined
undefined =x-2 is false
answer if no
but if your teacher says that it is true because of simplification tell that x=1 doesn't work
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Form an equation:
x + 15 + 7 + x = 14
Simplify :
2x + 22 = 14
Subtract 22 from both sides:
2x = -8
Divide both sides by 2:
x = -4
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Q1. The answers are (–1, 8), (0, 7), (3, 18)
<span>–3x + y ≥ 7
</span>Let's go through all choices:
<span>(–2, –3)
</span>(-3) * (-2) + (-3) ≥ 7
6 - 3 ≥ 7
3 ≥ 7 INCORRECT
(–1, 8)
(-3) * (-1) + 8 ≥ 7
3 + 8 ≥ 7
11 ≥ 7 CORRECT
(0, 7)
(-3) * 0 + 7 ≥ 7
0 + 7 ≥ 7
7 ≥ 7 CORRECT
(1, 9)
(-3) * 1 + 9 ≥ 7
-3 + 9 ≥ 7
6 ≥ 7 INCORRECT
(3, 18)
(-3) * 3 + 18 ≥ 7
-9 + 18 ≥ 7
9 ≥ 7 CORRECT
Q2. The answers are:
5x + 12y ≤ 80
x ≥ 4
<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes
</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
5x + 12y </span>≤ 80
Jude needs at least 4 small boxes on the shelf: x ≥ 4
Let's check if y can be 0:
5x + 12y ≤ 80
5x + 12 * 0 ≤ 80
5x + 0 ≤ 80
5x ≤ 80
x ≤ 80 / 5
x ≤ 16
x ≥ 4 can include x ≤ 16
So, y can be 0: y ≥ 0
Since you have to find the total amount he has you add 11+43 which is 54 so the answer is 54.
Answer:
Step-by-step explanation:
because y² + 4y + 5 = (y+2)² + 1 > 0, ∀ y ∈ R
=> y² + 4y + 5 = 0 is unreasonable
=> no solutions
