Expression J:
–12 ÷ (–3) – 20 ÷ 2 has a value of –6.
Solution:
To find which expression has a value of –6.
Solve these expressions using BODMAS rule.
Expression F: –4 · 2 – (–14)
–4 · 2 – (–14) = –4 · 2 + 14
= –8 + 14
= 6
Therefore, this is not true.
Expression G: –16 ÷ (–2) – (–2)
First do division by BODMAS rule.
–16 ÷ (–2) – (–2) = 8 – (–2)
= 8 + 2
= 10
Therefore, this is not true.
Expression H: –2 – (–8) ÷ (–1)
First do division by BODMAS rule.
–2 – (–8) ÷ (–1) = –2 – 8
= –10
Therefore, this is not true.
Expression J: –12 ÷ (–3) – 20 ÷ 2
First do division by BODMAS rule.
–12 ÷ (–3) – 20 ÷ 2 = 4 – 20 ÷ 2
= 4 – 10
= –6
This expression has a value of –6.
Hence it is true.
Therefore –12 ÷ (–3) – 20 ÷ 2 has a value of –6.
