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sergey [27]
3 years ago
13

A figure can be covered by 28 unit squares,without any gaps or overlaps.what is the area of the figure?

Mathematics
1 answer:
Tom [10]3 years ago
7 0
Remember that the area of a square is just one of its sides squared. A=s^2
where 
A is the area of the square 
s is one of the sides of the square

Unit square is a square whose sides have length 1, so lets use our formula to find the volume of one unit square:
A=s^2
A=1^2
A=1
We now know that each one of the squares has area 1 unit squared. Since there are 28 unit square in our figure, we are going to multiply the area of a unit square by 28 to find the area of our figure:
Area of the figure=28(1)=28 units squared 

We can conclude that the area of the figure is 28 units squared.
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Step-by-step explanation:

a.

Given

0 x < 3

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1 x > 4.13

Calculating E(x)

First, we'll calculate the pdf, f(x).

f(x) is the derivative of F(x)

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E(x) is the integral of xf(x)

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Integrating x/1.3

E(x) = x²/(2*1.13)

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E(x) = 3.730 (approximated)

b.

What is the value c such that P(X < c) = 0.75

First, we'll solve F(c)

F(c) = P(x<c)

F(c) = (c-3)/1.13= 0.75

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c = 3 + 0.8475

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c.

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Here we'll solve for

P(3.73 - 0.28 < X < 3.73 + 0.28)

= F(3.73 + 0.28) - F(3.73 + 0.28)

= 2*0.28/1.3 = 0.430769

= 0.4308 -- Approximated

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