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sergey [27]
3 years ago
13

A figure can be covered by 28 unit squares,without any gaps or overlaps.what is the area of the figure?

Mathematics
1 answer:
Tom [10]3 years ago
7 0
Remember that the area of a square is just one of its sides squared. A=s^2
where 
A is the area of the square 
s is one of the sides of the square

Unit square is a square whose sides have length 1, so lets use our formula to find the volume of one unit square:
A=s^2
A=1^2
A=1
We now know that each one of the squares has area 1 unit squared. Since there are 28 unit square in our figure, we are going to multiply the area of a unit square by 28 to find the area of our figure:
Area of the figure=28(1)=28 units squared 

We can conclude that the area of the figure is 28 units squared.
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Daniel has $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each , what is thw greatest num
kondor19780726 [428]
$25 is the total amount of money.
Admission is a constant, meaning that price will not vary and is fixed.
The rides each cost something so the price of rides will vary, unlike the constant (admission). 

Thus making x the number of rides, we have the equation:
25 = 4 + 1.5x.
We need to solve for x, but x must be a whole number so we will round down if the solution is not an integer.

1.5x = 21
Divide by 1.5 on both sides.
x=14

Daniel can go on 14 rides maximum.
8 0
3 years ago
Determine what type of model best fits the given situation: An Internet phone company presently provides service to 5,000 custom
bagirrra123 [75]

Answer:

The best fit is <em>A. Linear model</em>

<em></em>

Step-by-step explanation:

Given:

Monthly Rate = $20, Number of customers = 5000

If there is a decrease of $1 in the monthly rate, the number of customers increase by 500.

To find:

The type of model that best fits the given situation?

Solution:

Monthly Rate = $20, Number of customers = 5000

Let us decrease the monthly rate by $1.

Monthly Rate = $20 - $1  = $19, Number of customers = 5000 + 500 = 5500

Let us decrease the monthly rate by $1 more.

Monthly Rate = $19 - $1  = $18, Number of customers = 5500 + 500 = 6000

Here, we can see that there is a <em>linear change </em> in the number of customers whenever there is decrease in the monthly rate.

We have 2 pair of values here,

x = 20, y = 5000

x = 19, y = 5500

Let us write the equation in slope intercept form:

y =mx+c

Slope of a function:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{5500-5000}{19-20}\\\Rightarrow -500

So, the equation is:

y =-500x+c

Putting x = 20, y = 5000:

5000 =-500\times 20+c\\\Rightarrow c = 5000 +10000 = 15000

\Rightarrow \bold{y =-500x+15000}

Let us check whether (18, 6000) satisfies it.

Putting x = 18:

-500 \times 18 +15000 = -9000+15000 = 6000 so, it is true.

So, the answer is:

The best fit is <em>A. Linear model</em>

6 0
4 years ago
Complete each congruence statement by naming the corresponding angle or side (odd questions only)
Oksi-84 [34.3K]

Given:

1. \Delta HJI\cong \Delta IQP

3. \Delta JLK\cong \Delta FGH

To find:

The missing values to complete the congruence statements:

1. \overline{IH}\cong \_\_\_\_

3. \angle KJL\cong \_\_\_\_\_

Solution:

1.

We have,

\Delta HJI\cong \Delta IQP

Here, vertices H, J, I are corresponding to I, Q, P. So,

\overline{IH}\cong \overline{PI}

Therefore, the complete statement is \overline{IH}\cong \overline{PI}.

3.

We have,

\Delta JLK\cong \Delta FGH

Here, vertices J, L, K are corresponding to F, G, H. So,

\angle KJL\cong \angle HFG

Therefore, the complete statement is \angle KJL\cong \angle HFG.

4 0
3 years ago
Select Proportional or Not proportional to describe each equation.
arsen [322]

Answer:

All are not proportional

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Is this correct? Or wrong
hjlf
I believe you are right I checked the work and everything seems to be good !
8 0
3 years ago
Read 2 more answers
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