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Sati [7]
3 years ago
5

Justin wants to use 376ft of fencing to fence off the greatest possible rectangular area for a garden. What dimensions should he

use? What will be the area of the garden?
a. 89 x 99; 8811 ft
b. 92 x 96; 8832 ft
c. 94 x 94; 8836 ft
d. 93 x 95; 8835 ft
Mathematics
1 answer:
poizon [28]3 years ago
6 0
C. 94 x 94; 8836 ft because this is the greatest area.
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Who can help me out with this question???
GaryK [48]

Answer:

x = 13

Step-by-step explanation:

a^{2} +b^2 = c^2\\12^2 + 5^2 = c^2\\144 + 25 = c^2\\169 = c^2\\

Take the square root of both sides

\sqrt{169} = \sqrt{c^2} \\13 = c

8 0
3 years ago
Determine the average rate of change of the function between the given values of the variable. g(x)=2/x ; x=4, x=a
IrinaK [193]
Average rate of change implies the quotient f(4)-f(a)/4-a which equals (1/2-a/2)/4-a=(1-a)/(8-2a) on (4,a)
3 0
3 years ago
Please help me prove this theorem thing. I'll give yuh mind kisses <3 have a good day luvlies
lesantik [10]

Answer:

∠ 1 = 20 x + 5

∠ 2 = 24 x - 1

If lines l and m are parallel:

∠ 1 + ∠ 2 = 180°

20 x + 5 + 24 x - 1 = 180

44 x + 4 = 180

44 x = 180 - 4

44 x = 176

x = 176 : 44

x = 4°

Your welcome again :)

Step-by-step explanation:

6 0
3 years ago
How do you write the equation of this description: the graph of a parabola has a vertex of (2,3) and vertically stretched by 3
Mademuasel [1]

The equation of parabola is  y = 3x²- 12x+ 15.

<u>Step-by-step explanation:</u>

The equation of the parabola is given as y = x².

If it has a vertex then the equation can be written as,

y = a(x-h)² + k

where (h, k ) is the vertex and a is the stretching or compressing factor.

So here the vertex is (2,3) and it is vertically stretched by 3.

So the equation is given as,

y = 3(x-2)² + 3

y = 3(x² -4x+4) + 3

 = 3x² - 12x + 12 + 3

y = 3x²- 12x+ 15 is the equation of the parabola.

3 0
3 years ago
Help me please <br> !!!!!!!!!!!!!!!
Vitek1552 [10]

16 units. Start from -2 and count up to 14. Basically -2+2+2+2+2+2+2+2+2+2 since the scale is by 2

4 0
3 years ago
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