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Svetach [21]
4 years ago
6

Please help me with the explain one

Mathematics
1 answer:
Minchanka [31]4 years ago
7 0
That the absolute value of -18 is 18 away from 0
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Pls help with this question
Talja [164]

Answer:

point A is x=4 and y=12

point B is x=16 and y=32

6 0
2 years ago
Which one of the following is NOT true about the expression shown
garri49 [273]

Answer:

A) The expression is a trinomial.

Step-by-step explanation:

If the degree is 2, the expression would be a binomial, not a trinomial. If this answer is correct, please make me Brainliest!

7 0
3 years ago
H(t)=-10t+6<br> H(_____)=-44<br> Help me please.
alexira [117]

Answer:

-10t +6=-44

-10t=-44-6

-10t=-50

-50\-10

=5

8 0
3 years ago
What is the area of rhombus ABCD? do not round any steps
katrin2010 [14]
Because ABCD is a rhombus, ΔABC ~ ΔADC.

The length of AC = 4 (the base of ΔABC.
The height of ΔABC = 7 - 1 = 6
The area of ΔABC is
(1/2)*4*6 = 12

Therefore the area of ABCD = 2*12 = 24

Answer: 24

3 0
3 years ago
A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12. Suppose that we take a random
Zielflug [23.3K]

Answer: The 95% confidence interval for the mean of x is (94.08, 101.92) .

Step-by-step explanation:

We are given that ,

A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12.

i.e. \sigma= 12

Also, it is given that , Sample mean \overline{x}=98 having sample size : n= 36

For 95% confidence ,

Significance level : \alpha=1-0.95=0.05

By using the z-value table , the two-tailed critical value for 95% Confidence interval :

z_{\alpha/2}=z_{0.025}=1.96

We know that the confidence interval for unknown population mean(\mu) is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = Sample mean

\sigma = Population standard deviation

z_{\alpha/2} = Critical z-value.

Substitute all the given values, then the required confidence interval will be :

98\pm (1.96)\dfrac{12}{\sqrt{36}}

=98\pm (1.96)\dfrac{12}{6}

=98\pm (1.96)(2)

=98\pm 3.92=(98-3.92,\ 98+3.92)\\\\=( 94.08,\ 101.92)

Therefore, the 95% confidence interval for the mean of x is (94.08, 101.92) .

6 0
3 years ago
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