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3 years ago

Please help me with the explain one

Mathematics

1 answer:

Minchanka [31]3 years ago

7 0

That the absolute value of -18 is 18 away from 0

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A company packages their product in two sizes of cylinders each dimension of the largest cylinder is twice the size of the corre

Katarina [22]

The correct answer to your question is:
D. The volume of the cylinder is 8 times the volume of the smaller cylinder.

4 0

3 years ago

In its monthly report, the local animal shelter states that it currently has 24 dogs and 18 cats available for adoption. Eight o

andrezito [222]

Answer with Step-by-step explanation:

We are given that

Total dogs=24

Total cats=18

Total animals=24+18=42

Male dogs=8

Male cats=6

Total male animals=8+6=14

Total female animals=42-14=28

Female cats=18-6=12

Dogs female=24-8=16

a.We have to find the probability that the pet is male, given that it is cat.

It means we have to find P(Male/cat)

Conditional probability: $P(A/B)=\frac{P(A\cap B)}{P(B)}$

P(Cat)= $\frac{18}{42}$

$P(male cat)=\frac{6}{42}$

$P(Male/cat)=\frac{\frac{6}{42}}{\frac{18}{42}}$

P(male/cat)= $\frac{6}{18}=0.33$

b. $P(female cat)=\frac{12}{42}$

$P(female)=\frac{28}{42}$

$P(Cat/Female)=\frac{\frac{12}{42}}{\frac{28}{42}}=\frac{12}{28}=0.43$

c.P(Dog)= $\frac{24}{42}$

$P(dog female)=\frac{16}{42}$

$P(female/dog)=\frac{\frac{16}{42}}{\frac{24}{42}}$

$P(female/dog)=\frac{16}{24}=0.67$

5 0

3 years ago

To begin a bacteria study, a petri dish had 2800 bacteria cells. Each hour since, the number of cells has increased by 7.2%. Let

Rudiy27

The function that models exponential growth is:

P(t) = P0*(1 + r)^t, where

P0 = P(0) is the initial value of P

r is the growth rate as a decimal

In our case we have:

P(0) = 2800

r = 0.035 or 3.5%

P(t) = 2800*(1 + 0.035)^t

P(t) = 2800*(1.035)^t

The same exponential function written using y and t is:

y = 2800*1.035^t.

Explanation: https://softmath.com/algebra-word-problems/to-begin-a-bacteria-study-a-petri-dish-had-2800-bacteria

7 0

2 years ago

Find the first five terms of each geometric sequence described <br><br> A1=1 R=4

xenn [34]

$\bf n^{th}\textit{ term of a geometric sequence}
\\\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
r=\textit{common ratio}\\
a_1=\textit{first term}\\
-------\\
a_1=1\\
r=4
\end{cases}\\\\
-----------------------------\\\\
$

$\bf \begin{array}{ccllll}
term&value\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1&a_1=1\\
2&a_2=a_1\cdot 4^{2-1}\\
3&a_3=a_1\cdot 4^{3-1}\\
4&a_4=a_1\cdot 4^{4-1}\\
5&a_5=a_1\cdot 4^{5-1}\\
\end{array}$

3 0

3 years ago

When making a horizontal translation your y-value changes and when making a vertical translation your x-value changes. true or f

Ann [662]

False
The horizontal translation is from left to right which affects the x-value while the vertical translation is up to down which affects the y-value

Good luck!

3 0

2 years ago