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lana [24]
3 years ago
14

14x^2-8x+3 + -6x^2+7x-11

Mathematics
2 answers:
Simora [160]3 years ago
8 0
8x^2-x-8 

:P yay I got the answer after about 10 minutes of work XD
Bingel [31]3 years ago
7 0
Your answer is 8x^2-x-8. hope this helps
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Step-by-step explanation:

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Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

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Answer: correct option is B.

7 0
3 years ago
What is the value of the fourth term in a geometric sequence for which a1 = 30 and r = 1/2?.
Mariana [72]
\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=30\\
r=\frac{1}{2}\\
n=4
\end{cases}\implies a_4=30\left( \frac{1}{2} \right)^{4-1}
5 0
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PLS HElp PLZZZZZZZZZZZZZZZZZZZ
natali 33 [55]

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c

Step-by-step explanation:

they use multiples of 9

4 0
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