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allsm [11]
3 years ago
9

The number of students at valley view middle school increased by 10%, To 770 total students were endrolled at valley view middle

school before increase?
Mathematics
1 answer:
alexgriva [62]3 years ago
5 0
Before the increase, there were 693 students
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Find the measure of line f and g
kiruha [24]

In this case we use intersecting secant theorem  

According to this theorem, GF*GE = GH*GA

So,we plug in the values

(x-3)*(x-3+9) =(x-2)*(x-2+6)

(x-3)*(x+6) =(x-2)*(x+4)

x^2 +6x -3x -18 =x^2 +4x -2x -8

x^2 +3x -18 =x^2 +2x -8

x^2 +3x -18 -x^2 -2x +8 =0

x -10 =0

x=10

So,FG =x-3 = 10-3 =7

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3 years ago
What are the zeros of this function?
Marina86 [1]
Where is the function?
7 0
3 years ago
If 4x-1=X, Find 30x<br> a) 10 b) 40<br> C) 12 d)11<br><br> How do you solve this?
cestrela7 [59]

Answer:

(a)

Step-by-step explanation:

Given

4x - 1 = x ( subtract x from both sides )

3x - 1 = 0 ( add 1 to both sides )

3x = 1 ( multiply both sides by 10 )

30x = 10 → (a)

3 0
3 years ago
What is the solution to the equation e^3x=12 Round your answer to the nearest hundredth
Lunna [17]

Keywords:

<em>equation, variable, clear, round, centesima, neperian logarithm, exponential </em>

For this case we have the following equation e ^ {3x} = 12, from which we must clear the value of the variable "x" and round to the nearest hundredth. To do this, we must apply properties of neperian and exponential logarithms. By definition:

ln (e ^ x) = x

So:

e ^ {3x} = 12 We apply Neperian logarithm to both sides:

ln (e^{3x}) = ln (12)\\3x = ln (12)

We divide between "3" both sides of the equation:

\frac {3x} {3} = \frac {ln (12)} {3}\\x = \frac {ln (12)} {3}\\x = 0.828302217

Rounding out the nearest hundredth we have:

x = 0.83

Answer:

x = 0.83

3 0
3 years ago
Read 2 more answers
Two step equation, last one thank you for helping
DerKrebs [107]

just do 2.80-0.75 and you'll get your original which is 2.05 for the 2nd past

for the 1st one I'd do 2.80 divided by 0.75 and I would get  37 cents

7 0
3 years ago
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