C = 5/9(F - 32)
C = -30
-30 = 5/9(F - 32)
-30 = 5/9F - 160/9
-30 + 160/9 = 5/9F
-270/9 + 160/9 = 5/9F
-110/9 = 5/9F
-110/9 * 9/5 = F
- 990/45 = F
- 22 = F
C = 5/9(F - 32)
C = 130
130 = 5/9F - 160/9
130 + 160/9 = 5/9F
1170/9 + 160/9 = 5/9F
1330/9 = 5/9F
1330/9 * 9/5 = F
11970/45 = F
266 = F
So in Fahrenheit temp, the the car is protected between -22 F and 266 F
Answer:
4.57 x 
Step-by-step explanation: use ma th way next time and use it to see the steps
Answer:
6
Step-by-step explanation:
XY = 3x – 1, YZ = 5, and XZ = 5x – 8,
We know that XY + YZ = XZ, so
3x - 1 + 5 = 5x - 8
3x + 4 = 5x - 8
3x + 12 = 5x
12 = 2x
6 = x
∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.
... ∠1 = ∠2
... 3x -5 = 2x +15 . . . . substitute the given values
... x = 20 . . . . . . . . . . . add 5-2x
The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.