3.5r.....................
Answer:
A -6 divided by (-3)
Step-by-step explanation:
pls give brainliest!!! i would REALLY appreciate it! hope i helped :3
The expression for the distance the car travels after t seconds is d = 200t + 50t²
<h3>Equation of motion </h3>
From the question, we are to write an expression for the distance the car travels after t seconds
From the given information,
The equation for the motion of an object with constant acceleration is
d = vt + 0.5at²
For the race car,
v = 200 ft/s
a = 100 ft/s²
Putting the parameters into the equation, we get
d = 200t + 0.5(100)t²
d = 200t + 0.5 ×100)t²
d = 200t + 50t²
Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²
Learn more on Equations of motion here: brainly.com/question/20910641
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Answer:
lets say they are a,b,c,d
a*b*c*d=67184
a<10
a=d-30
also bear in mind that b and c are in between
the rest is just trial and error as long as you satisfy all those equations above
Step-by-step explanation:
Answer:
The answer is C
Step-by-step explanation:
By using the quadratic formula, you get
a=1
b=5
c=7
so, when you substitute, you get:
-5±√5²-4(2)(7)
____________
2(1)
The next step is solving the square root and multiplying