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2 years ago

Use the given graph to determine the limit, if it exists.

1 answer:

4 0

<span>"A coordinate graph is shown with a horizontal line crossing the y axis at three that ends at the open point 2, 3," → follow this for the Left limit, so this one would be 3

"</span><span> another horizontal line starting at the open point 2, -2. " → follow this for the right limit, so it's -2</span>

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Need Help pleasee.. I have attached the question below.. For the quick and correct answer I will give 10 points and brainliest

kirill [66]

A equals 3
Equation is g(x)=3f(x)

What i did is notice the y intercept is at 3 so I plugged in x=0 into the parent equation and got f(0)=1

So to get this equation to the y=3 intercept which is the g function, you have to multiply it by 3

5 0

2 years ago

Theresa has two brothers,Paul and Steve, who are both the same height. Paul says he is 16 inches shorter than 1 1/2 times Theres

shepuryov [24]

Answer:

Theresa's height is 60 inches

Step-by-step explanation:

The given parameters are;

The height of Paul = The height of Steve

Paul's height = $1\dfrac{1}{2}$ times Theresa's height - 16 inches

Steve's height = $1\dfrac{1}{3}$ times Theresa's height - 6 inches

Let 'T' represents Theresa's height, we have;

Paul's height = $1\dfrac{1}{2}$ ×T - 16

Steve's height = $1\dfrac{1}{3}$ ×T - 6

Paul's height = Steve's height

Therefore;

$1\dfrac{1}{2}$ ×T - 16 = $1\dfrac{1}{3}$ ×T - 6

$1\dfrac{1}{2}$ ×T - $1\dfrac{1}{3}$ ×T = 10

$#\dfrac{3}{2}$ ×T - $\dfrac{4}{3}$ ×T = 10

$\dfrac{1}{6}$ ×T = 10

T = 10 × 6 = 60

Theresa's height, T = 60 inches

5 0

2 years ago

2) Jose recently saw an ad online for a new version of his tablet. The projected price is $450, and the phone will be out on the

soldi70 [24.7K]

Answer:

462.38

Step-by-step explanation:

bc its only a year and it is inflated by 2.75% xoxox

3 0

2 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$