Answer:
The product of something is what you get after you multiply two numbers together
Step-by-step explanation:
By definition we have to:
Sin (x) = C.O / h
Where,
x = angle
C.O = opposite leg
h: hypotenuse.
Substituting values we have:
Sin (C) = AB / 82
We should look for AB. For this, we use the following relationship:
AB ^ 2 + 80 ^ 2 = 82 ^ 2
Clearing AB:
AB = root ((82 ^ 2) - (80 ^ 2))
AB = 18
Substituting we have:
Sin (C) = 18/82
Simplifying:
Sin (C) = 9/41
Answer:
the trigonometric ratio for sin C is:
Sin (C) = 9/41
This is a hexagonal prism: Volume = Area of Base (hexagon) x Height:
There are 6 equal equilateral triangles in a hexagone.
The apothem (or altitude of each triangle) = side x (√3)/2 =12(√3)/2 = 6√3
Area of ONE equilateral triangle = (side x altitude)/2:
Area of ONE equilateral triangle = (12 x 6√3)/2 = 36√3 ft²
Area of the SIX equilateral triangles = 36√3 x 6 = 216√3 ft²
VOLUME = BASE X HEIGHT = 216√3 x 15 = 3240√3 ft³
OR VOLUME = 5612 ft³
Multiple values of y for a single value of x is a sure giveaway that this is NOT a function. Please review definitions of "function." A function would be represented if no x value has more than one y value associated with it.
The striped rectangle has a total area of 69,375 cm².
<h3>How to calculate the area of the
striped rectangle?</h3>
To find the area of the striped rectangle we must carry out the following procedures.
Find the area of each segment of the rectangle, that is, what is the area of each of the 24 squares that make up the rectangle, for that we divide the 111cm² of the total area into 24.
According to the above, we infer that each square has an area of 4.625cm².
On the other hand, to find the area of the striped rectangle we must take into account that it is 5 squares long by 3 squares high, that is, its area is 15 squares.
Finally, each square has an area of 4.625cm², so to find the total area of the striped area we must multiply the area of each square by the number of squares.
15 × 4.625cm² = 69.375cm²
Learn more about areas in: brainly.com/question/27683633
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