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3 years ago

7

There are 100 Skittles. 94 are blue and 6 are red. If you take 5 Skittles, what’s the chance one will be red? What’s the chance

all 5 will be red?

1 answer:

Art [367]3 years ago

7 0

Answer:

6/100 +94/100

3/50 +47/50

3+47/50

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Rewrite 6(10+2) using the distributive property. Then simply.

Montano1993 [528]

$\begin{gathered} 6(10+2)=(6\cdot10)+(6\cdot2) \\ 6(10+2)=60+12 \\ 6(10+2)=72 \end{gathered}$

Explanation

the distributive property states that multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together

$a(b+c)=ab+ac$

so

Step 1

$6(10+2)$

apply the distributive property

$6(10+2)=(6\cdot10)+(6\cdot2)$

now, calculate ot simplify

$\begin{gathered} 6(10+2)=(6\cdot10)+(6\cdot2) \\ 6(10+2)=60+12 \\ 6(10+2)=72 \end{gathered}$

I hope this helps you

5 0

1 year ago

N+5/16=-1 what is the answer?

juin [17]

$\frac{n+5}{16}=-1$

$n+5=-16$

$n=-21$

5 0

3 years ago

Read 2 more answers

The population of the United States was about 280 million in 2000 and about 310 million in 2010. What was the annual rate of cha

makkiz [27]

Ok, find change then divide by years elapsed

change=310-280 million=30 million

number of years elapsed=10
30mil/10=3mil

3million per year was the population growth rate

6 0

3 years ago

Read 2 more answers

1 − 3(3 + 6b) = −6(3b + 1) − 2 <br> will get brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!

Zarrin [17]

Answer:

=infinite

Step-by-step explanation:

7 0

3 years ago

Given f(x)=2x^2+3x-5 for what values of x is f(x) positive

kow [346]

Answer:

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

Step-by-step explanation:

we have

$f(x)=2x^{2}+3x-5$

This is a vertical parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The coordinates of the vertex is the point (h,k)

step 1

Find the vertex of the quadratic function

Factor the leading coefficient 2

$f(x)=2(x^{2}+\frac{3}{2}x)-5$

Complete the square

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}$

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}$

Rewrite as perfect squares

$f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}$

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

step 2

Find the x-intercepts (values of x when the value of f(x) is equal to zero)

For f(x)=0

$2(x+\frac{3}{4})^{2}-\frac{49}{8}=0$

$2(x+\frac{3}{4})^{2}=\frac{49}{8}$

$(x+\frac{3}{4})^{2}=\frac{49}{16}$

take the square root both sides

$x+\frac{3}{4}=\pm\frac{7}{4}$

$x=-\frac{3}{4}\pm\frac{7}{4}$

$x_1=-\frac{3}{4}+\frac{7}{4}=1$

$x_2=-\frac{3}{4}-\frac{7}{4}=-2.5$

therefore

The function f(x) is negative in the interval (-2.5,1)

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

see the attached figure to better understand the problem

6 0

4 years ago