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3 years ago

7

There are 100 Skittles. 94 are blue and 6 are red. If you take 5 Skittles, what’s the chance one will be red? What’s the chance

all 5 will be red?

1 answer:

Art [367]3 years ago

7 0

Answer:

6/100 +94/100

3/50 +47/50

3+47/50

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A bowl weighs 11/40<br> lb. Express this as a decimal.

Ivanshal [37]

Answer:

Decimal: 0.275 Percentage: 27.5

Step-by-step explanation:

4 0

3 years ago

When 10 b = 5 (StartRoot c EndRoot + 2) is solved for c, one equation is c = (2b minus 2) squared Which of the following is an e

Burka [1]

Answer:

I will show all the steps to lead to the solution.

1) 10b = 5 (√c + 2) <---- starting equation

2) divide by 5 => 2 b = √c + 2

3) subtract 2 => 2b - 2 = √c

4) raise to the power 2 => (2b - 2)^2 = c, which is the expression given.

Now these are two equivalent forms:

1) extract 2 from the parentheses: c = 4 (b -1)^2

2) expand the parentheses: c = 4b^2 - 8b + 4)

Step-by-step explanation:

Choice D

8 0

3 years ago

In 2007, the U.S. population was 302 million people. In 2012, it was 314 million. What was the rate of population change per yea

allsm [11]

Answer:

314/302=1.039735 growth in US population in 5 years

(1.039735)^1/5=0.782% average growth in US population per year.

6 0

3 years ago

2/3 b + 5 =20 - b solve for b

Wittaler [7]

Answer:

$b = 9$

Step-by-step explanation:

$\frac{2}{3} b + 5 = 20 - b$

In order to solve for b, we must isolate the variable. We can start by subtracting 5 from both sides.

$\frac{2}{3} b + 5 - 5 = 20 - b - 5$

Simplify.

$\frac{2}{3} b = 15 - b$

Add b to both sides.

$\frac{2}{3} b + b = 15 - b + b$

Simplify.

$\frac{2}{3} b + b = 15$

Multiply everything by 3 to remove the fractions.

$3(\frac{2}{3}b+b) = 3(15)$

Simplify.

2b + 3b = 45

Simplify.

5b = 45

Divide 5 from both sides.

5b ÷ 5 = 45 ÷ 5

Simplify.

b = 9

For more information on solving variables, check out the following answers!

4 0

2 years ago

Read 2 more answers

Given that f(x) = x + 3<br> a) Find f(2)

Nataly_w [17]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

In the above question, it is given that :

$\qquad \sf \boxed{ \sf f(x) = \frac{x + 3}{2} }$

A.) Find f(2) :

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{2 + 3}{2}$

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{5}{2}$

or

$\qquad \sf \dashrightarrow \: f(2) = 0.5$

B.) Find ${ \sf {f}^{-1}(x) }$ :

$\qquad \sf \dashrightarrow \: let \: y = f (x)$

so, we can write it as :

$\qquad \sf \dashrightarrow \: y = \dfrac{x + 3}{2}$

$\qquad \sf \dashrightarrow \: 2y = x + 3$

$\qquad \sf \dashrightarrow \: x = 2y - 3$

Now, put x = ${ \sf {f}^{-1}(x) }$ , and y = x and we will get our required inverse function ~

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3$

C.) Find ${ \sf {f}^{-1}(12) }$ :

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 36- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 33$

7 0

1 year ago