Question

A parent that is heterozygous for both traits (AaBb) can create how many different allele possibilities.

Answer 1

Distribute the A to the B and the b, then the a to the B and the b. You should get four different possible combinations: AB Ab aB ab. These would then be used to set up one side of a punnett square, and the other parent's genotype would be set up the same, then put on the other side of the punnett square.