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3 years ago

If 4x^2 - 100 = 0 then the roots of the equation are

2 answers:

8 0

4x² - 100 = 0
 + 100 + 100
 4x² = 100
 4 4
 x² = 25
 x = +5
4(5)² - 100 = 0
4(25) - 100 = 0
100 - 100 = 0
 0 = 0

4(-5)² - 100 = 0
4(25) - 100 = 0
 100 - 100 = 0
 0 = 0

The roots of the equation is positive or negative 5.

Alex17521 [72]3 years ago

6 0

4x^2-100=0
4x^2=100
x^2=100/4
x^2=-25
x=5 or x=-5

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3 years ago

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Solve the triangle. Round your answers to the nearest tenth. A. m∠A=43, m∠B=55, a=16 B. m∠A=48, m∠B=50, a=23 C. m∠A=48, m∠B=50,

alexgriva [62]

Answer:

D. m∠A=43, m∠B=55, a=20

Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

AB = c = 29

AC = b = 24

Required:

m<A, m<C, and a (BC)

SOLUTION:

Find m<B using the law of sines:

$\frac{sin(B)}{b} = \frac{sin(C)}{c}$

$\frac{sin(B)}{24} = \frac{sin(82)}{29}$

$sin(B)*29 = sin(82)*24$

$\frac{sin(B)*29}{29} = \frac{sin(82)*24}{29}$

$sin(B) = \frac{sin(82)*24}{29}$

$sin(B) = 0.8195$

$B = sin^{-1}(0.8195)$

$B = 55.0$

m<B = 55°

Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

m<A = 43°

Find a using the law of sines:

$\frac{a}{sin(A)} = \frac{b}{sin(B)}$

$\frac{a}{sin(43)43} = \frac{24}{sin(55)}$

Cross multiply

$a*sin(55) = 25*sin(43)$

$a = \frac{25*sin(43)}{sin(53)}$

$a = 20$ (approximated)

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3 years ago

If angle YWZ = 17, what is angle WXY?

marusya05 [52]

We know that

step 1
if ∡YWZ=17°
then
∡XWZ=17°*2-----> 34°----> because triangle XWY and triangle YWZ are congruents

step 2
∡WXY=∡WZY-------> because triangle XWY and triangle YWZ are congruents
we know that
the sum of the internal angles of a triangle is 180 degrees
so
180°=∡XWZ+2*∡WXY---------> ∡WXY=[180-∡XWZ]/2
∡WXY=[180-34°]/2-------> ∡WXY=73°

the answer is
∡WXY=73°

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