The answer is A 7 hope it helps <3
Since the motor boat left the dock 2 hours before the tour boat, their meeting point will be 27 miles from the dock from which both boats departed after 3 hours.
<h3>What is the distance?</h3>
Distance is the movement of an object regardless of direction. The distance can be defined as the amount of length an object has covered, regardless of its starting or ending position
We know that r × t = d
r = rate of speed
t = time
d = distance
For the motor boat
9 × t = d = rate × time
For the tour boat
27 × (t - 2) = d = rate × time
When they both cover the same distance in the same amount of time, they will eventually cross paths.
They both cover the same d-mile distance, so:
9 ×t = 27 × (t - 2)
Simplify to get:
9 × t = 27 × t - 54
18 t = 54
t = 3
The motor boat will have traveled at 9 mph for 3 hours to make a distance of 9 × 3 = 27 miles.
The tour boat will have traveled at 27 mph for 1 hour to make a distance of 1 × 27 = 27 miles.
Since the motor boat left the dock 2 hours before the tour boat, their meeting point will be 27 miles from the dock from which both boats departed after 3 hours.
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Rectangular form:
z = -2.1213203-2.1213203i
Angle notation (phasor):
z = 3 ∠ -135°
Polar form:
z = 3 × (cos (-135°) + i sin (-135°))
Exponential form:
z = 3 × ei (-0.75) = 3 × ei (-3π/4)
Polar coordinates:
r = |z| = 3 ... magnitude (modulus, absolute value)
θ = arg z = -2.3561945 rad = -135° = -0.75π = -3π/4 rad ... angle (argument or phase)
Cartesian coordinates:
Cartesian form of imaginary number: z = -2.1213203-2.1213203i
Real part: x = Re z = -2.121
Imaginary part: y = Im z = -2.12132034
D: We solve this in exactly the same way in which we solved the previous area problem. Side length is s, area is s^2. Here, side length is 5 in; area is 25 in^2.
the problem does say, however, not to include units in your answer. Thus, just write "25."
