1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natasha2012 [34]
3 years ago
14

Which number has a 3 with a value that is 100 times greater than the value of 3 in 20.342 ?

Mathematics
2 answers:
guapka [62]3 years ago
7 0

Answer:

Step-by-step explanation:

You want just any number?

Then the answer will be 0.3 * 100 = 30.

So you want a number where 3 is in the tens place.

Well one example is 738.3

There is a 3 in the tens place. The next number in the units is 8

Elodia [21]3 years ago
4 0

Answer:

You didnt give any options, but I'm guessing one of them has a 3 in the tens digits, which should be the right answer.

Step-by-step explanation:

You might be interested in
How do you solve (6,-7)(3,-5)
Masteriza [31]

are u looking for the slope?

5 0
3 years ago
Classify each polynomial according to its degree and type. Look at the screenshot below!
Ahat [919]

Answer:

                  Monomial    Binominal     Trimoninal

Degree 1:        -9x               x + 6

Degree 2:       -4x^{2}             4x^{2} -x       x -3x^{2} + 1

Degree 3:        4x^{3}            5 - 2x^{3}         3x^{2}  + 3x^{3} -10

Step-by-step explanation:

I do not know how to explain how I got to this answer, but here is the answer.

8 0
1 year ago
According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the
FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let P(t) be the amount of ^{235}U and Q(t) be the amount of ^{238}U after t years.

Then, we obtain two differential equations

                               \frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q

where k_1 and k_2 are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

Hence,

                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

We can use this fact to determine the numeric values of the decay constants k_1 and k_2. Thus,

                     4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}

and

                     7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}

Therefore,

                              P  = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q  = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}

We have that

                                          \frac{P(t)}{Q(t)} = 137.7

Hence,

                                   \frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7

Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

5 0
3 years ago
What is 9801 divided 99
irinina [24]

9801/99= 99


I hope that's help !

5 0
3 years ago
Estimate the answear by rounding each number to its greatest place: 199 x 91
Nataly [62]
I estimated the answer to be 18,000

Without estimation the answer would be 18,109
3 0
3 years ago
Read 2 more answers
Other questions:
  • You select a letter randomly from a bag containing the letters s, p, i, n, n, e, and r. find the probability of selecting an s.
    8·2 answers
  • Find the length of the missing side <br>The length of the missing side is​
    8·2 answers
  • A new truck that sells for $29,000 depreciates (decreases in value) 12% each year. Which function models the value of the truck?
    12·2 answers
  • the scatter plot shows the number of students per class al monida middle school and the number of magazine subscription each cla
    8·2 answers
  • The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this yea
    14·1 answer
  • Which point on the number line shown would represent the fraction 3/20?
    15·1 answer
  • Lanie’s room is in the shape of a parallelogram.
    13·1 answer
  • Find the area of the parallelogram. 7 in. 12 in. [ ] Area = [?] in.​
    10·1 answer
  • Lily is baking cookies for her office holiday party. Each batch of cookies needs 0.4 cups of sugar and 0.01 cups of cinnamon. If
    6·2 answers
  • Please help me please
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!