Here is a set of data: 11, 14, 10, 12, 19, 15, 18, 22, 8. what is the median?

How many 2/3 ounce portions of chocolate can Anna get from the 42/3 ounces of chocolate she bought at Union Market?

Lelechka [254]

She can get 21 portions. Since 2/3 and 42/3 already share the same denominator, all you need to do is divide 42 by 2 to get 21.

6 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$

It has critical points where the first order derivatives vanish:

$L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}$

$L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y$

$L_\lambda=x^2+y^2-4=0$

From the first two equations we get

$-\dfrac1{2x}=-\dfrac4y\implies y=8x$

Then

$x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}$

At these critical points, we have

$f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125$ (maximum)

$f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125$ (minimum)

5 0

3 years ago

Ernesto tried to determine the solution for the system of equations using substitution. His work is shown below.

defon

The answer is step 3. Step 2 is suppose to be 3 x 7 and the answer is 21 but he writes 7 in step 4

4 0

3 years ago

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A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin

Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean $\mu=50$

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

$P(X\leq 55)=1-P(X>55)$

$P(X\leq 55)=1-0.14$

$P(X\leq 55)=0.86$

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

$z=\frac{x-\mu}{\sigma}$

Where, $\sigma$ is standard deviation

Substitute the values,

$z=\frac{x-\mu}{\sigma}$

$1.08=\frac{55-50}{\sigma}$

$1.08=\frac{5}{\sigma}$

$\sigma=\frac{5}{1.08}$

$\sigma=4.62$

The standard deviation of weight for this species of cockroaches is 4.62.

4 0

2 years ago

What is 37 years converted into hours?

natta225 [31]

There are 24 hrs in a day, and there are 365 days in an year

first step: multiply years with days

37 x 365 = 13505 days in all

second step: multiply days with hrs

13505 x 24 = 324120 hrs

your total is 324120 hrs

hope this helps

6 0

3 years ago

Read 2 more answers