<span>2x + 9y = 0 (1st)
</span><span>3x + 5y = 17 (2nd)
multiply (st) by 3 and (2nd) by 2
</span>6x + 27y = 0 (1st)
6x + 10y = 34 (2nd)
----------------------------subtract
17y = -34
y = -2
2x + 9y = 0
2x +9(-2) = 0
2x = 18
x = 9
answer
(9, -2)
<h3><u>Question</u><u>:</u></h3>
<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. If the sum of the digits of the original number is 13, then find the number. </u>
<h3><u>Statement</u><u>:</u></h3>
<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. </u><u>T</u><u>he sum of the digits of the original number is 13</u><u>.</u>
<h3><u>Solution:</u></h3>
- Let one of the digit of the original number be x.
- So, the other digit = (13-x)
- Therefore, the two digit number = 10(13-x) + x = 130-10x+x = 130-9x
- The number obtained after interchanging the digits is 10x+(13-x) =9x+13
- Therefore, by the problem
130-9x-(9x+13) = 45
or, 130-9x- 9x-13 = 45
or, -18x = 45-130+13
or, -18x= -72
or, x = 72/18 = 4
or, x = 4
- So, the original number = 130-9x = 130 -9(4) = 130 - 36 = 94
<h3>Answer:</h3>
The number is 94.
I think the answer you have given isn't right. The answer should be 94.
knowing the answer is between 3 & 4 plug those as x and see what you get for answers than adjust the number accordingly
3^3+2(3) = 33 so its higher than 3
4^3 + 2(4) = 72 so it is lower than 4
try the middle so try 3.5
3.5^3 + 2(3.5) = 49.875
question states use 1 decimal place so now try 3.6
3.6^3+2(3.6) = 53.856
3.5 is closest
