How do i simply the expression??

G(x)=3x^2+6x−9<br><br> I need the vertex for this please

aleksley [76]

Answer:

-1, -12

Step-by-step explanation:

you take b which is 6 and make it negative, then you take a and multiply it by 2, which is 6. you then take the 2 numbers and put the -b over 2a in this formula -b/2a giving you -1 as your x value

after you do that, you input the -1 into the equation as x and the value you get out of that (-12) is the y value of the vertex

5 0

3 years ago

Given f of x is equal to the quantity x minus 4 end quantity divided by the quantity x squared plus 13x plus 36 end quantity, wh

gavmur [86]

The simplified expression of the function $f(x) =\dfrac{x-4}{x^2+13x+36}$ is

$f(x) = \dfrac{x-4}{(x+9)(x+4)}$ . f(x) is increasing for all x > –4.The correct answer is option C.

<h3>What is a function?</h3>

A function is defined as a relation between the set of inputs having exactly one output each.

The function expression is given as:

$f(x) =\dfrac{x-4}{x^2+13x+36}$

Expand the denominator

$f(x) =\dfrac{x-4}{x^2+4x +9x+36}$

Factorize the denominator

$f(x) =\dfrac{x-4}{x(x+4)+9(x+4)}$

Factor out x + 9

$f(x) = \dfrac{x-4}{(x+9)(x+4)}$

The simplified expression of the function $f(x) =\dfrac{x-4}{x^2+13x+36}$ is

$f(x) = \dfrac{x-4}{(x+9)(x+4)}$ . f(x) is increasing for all x > –4

Read more about functions at:

brainly.com/question/1851758

#SPJ1

8 0

2 years ago

The lengths of three sides of a quadrilateral are shown below:

julsineya [31]

Answers:
Part A: 12y² + 10y – 21
Part B: 4y³ + 6y² + 6y – 5
Part C: See below.

Explanations:
Part A:
For this part, you add Sides 1, 2 and 3 together by combining like terms:
Side 1 = 3y² + 2y – 6
Side 2 = 4y² + 3y – 7
Side 3 = 5y² + 5y – 8
3y² + 2y – 6 + 4y² + 3y – 7 + 5y² + 5y – 8
Combine like terms:
3y² + 4y² + 5y² + 2y + 3y + 5y – 6 – 7 – 8
12y² + 10y – 21

Part B:
You have the total perimeter and the sum of three of the sides, so you just need that fourth side value, which we can call d.
P = 4y³ + 18y² + 16y – 26
Sides 1, 2 & 3 = 12y² + 10y – 21
Create an algebraic expression:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
– 12y² – 12y²
10y – 21 + d = 4y³ + 6y² + 16y – 26
– 10y – 10y
– 21 + d = 4y³ + 6y² + 6y – 26
+ 21 + 21
d = 4y³ + 6y² + 6y – 5

Part C:
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y², y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms.

7 0

3 years ago

Anyone know how to find the area with the missing hypotenuse? Thank you!!!

suter [353]

Answer:

$15 {cm}^{2}$