The measures of two sides of a triangle are 3x + 4y and 5x - y. If the perimeter is 10x + 5y, find the measure of the third side.
<span>Let measure of the 3rd side be 'b'. </span>
<span>Substitute the values of length of the two sides and perimeter in equation and solve for b. </span>
<span>So, 10x + 5y = 3x + 4y + 5x - y + b..........[Substitute the values] </span>
<span>10x + 5y = 8x + 3y + b </span>
<span>(10x + 5y) - (8x + 3y) = b </span>
<span>10x + 5y - 8x - 3y = b </span>
<span>10x - 8x + 5y - 3y = b </span>
<span>2x + 2y = b </span>
<span>So, the measure of the third side is 2x + 2y. </span>
Plug the 7 in where it says x.
3x-4
3(7)-4
21-4
17
Equation (26.00-15.50) ÷1.50
Answer 7 rides
Solve $26 minus $15.50 equal $10.50 then divide 10.50 by 1.50 and you’ll get 7
Your best answer choice is A). because 62.00 x 30% = 18.6. Then 62.00 - 18.60 = 43.40
Answer:side+side+side+side
Step-by-step explanation:
