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never [62]
3 years ago
15

Can you solve the equation 2/3(4x-5)=8 by using the Division Property of Equality? Explain.

Mathematics
1 answer:
Nata [24]3 years ago
3 0
To solve for X you need to simplify both sides on the equation 
<span><span><span>23</span><span>(<span><span>4x</span>−5</span>)</span></span>=8

</span><span><span><span><span>(<span>23</span>)</span><span>(<span>4x</span>)</span></span>+<span><span>(<span>23</span>)</span><span>(<span>−5</span>)</span></span></span>=8 *</span>Distribute*

<span><span><span><span>8/3</span>x</span>+<span><span>−10/</span>3</span></span>=<span>8

after that you add 10/3 on both sides 

</span></span><span><span><span><span><span>8/3</span>x</span>+<span><span>−10/</span>3</span></span>+10/3</span>=<span>8+10/3</span></span><span><span><span>8/3</span>x</span>=<span>34/<span>3

finally multiply 3/8 on both sides 
</span></span></span><span><span>(<span>3/8</span>) x </span><span>(<span><span>8/3</span>x</span>)</span></span>=<span><span>(<span>3/8</span>) x </span><span>(<span>34/3</span><span>)

and your answer should be 
X= 17/4
</span></span></span>
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sleet_krkn [62]

Answer:

2x^2+3x is the expression which is equivalent to  x\left(2x+3\right).

In other words:

x\left(2x+3\right)=2x^2+3x

Step-by-step explanation:

Given the expression

x\left(2x+3\right)

solving

x\left(2x+3\right)

\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac

a=x,\:b=2x,\:c=3

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=2xx+3x

=2x^2+3x            ∴  2xx=2x^2

Thus,

x\left(2x+3\right)=2x^2+3x

Therefore, 2x^2+3x is the expression which is equivalent to  x\left(2x+3\right).

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