You could go both ways with this question, and they're both true:
-- circle "greatest" in both places;
-- circle "least" in both places; also true, but whatever the numbers are,
their least common factor is always ' 1 ', so it's not very useful.
Answer:
124858
Step-by-step explanation:
The first 4 digits are simple, you multiply the first digit of the equation by the 2nd digit and then for the other 2 you multiply the first digit of the equation by the 3rd digit.
6 + 2 + 8
6 * 2 = 12
6 * 8 = 48
Then the last 2 digits are the sum of the products of the 1 and 2 and 1 and 3 and subtract it by the 2
12 + 48 = 60
60 - 2 = 58
Put them together
Given p: 10 < 7, clearly p is false and ~p is true. Also, given q: 10 < 5, clearly q is false and ~q is true.
Thus, the truth value of the conditional statement ~p → ~q is <span>T T → T.</span>
The answer is <a is congruent to < d
because you already have <abe = <dbe