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weeeeeb [17]
3 years ago
6

Ben's Auto Dealer had a sale on Saturday for its new cars. By 10 a.m. 30% of the new cars had been sold. What decimal represents

the percent of cars that have not been sold by 10 a.m.?
Mathematics
2 answers:
emmasim [6.3K]3 years ago
4 0
Decimal: 0.7 100%-30%=70% 70%=70/100= 0.7
Deffense [45]3 years ago
3 0
.7 cars have not been sold
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51/22 hope this helps BRAINLIEST??
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Maya had $27. She spent all the money on buying 3 burgers for $x each and 2 sandwiches for $y each. If Maya would have bought 2
defon

Answer:

Option C

The student's conclusion is correct because the solution to the system of equations 3x+2y=27  and 2x+y=16 is (5,6)

Step-by-step explanation:

Let

x------> the cost of each burger

y-----> the cost of each sandwich

we know that

3x+2y=27 -----> equation A

2x+y=(27-11)

2x+y=16 ----> equation B

Solve the system of equations

Multiply the equation B by -2

-2(2x+y)=-2*16 ----->-4x-2y=-32 ------> equation C

Adds equation A and equation C

3x+2y=27 \\-4x-2y=-32\\ ----------\\ 3x-4x=27-32\\ -x=-5\\x=5

Substitute the value of x in the equation B

2(5)+y=16

10+y=16

y=6

The solution of the system of equations is the point (5,6)

so

The price of each burger is \$5

The price of each sandwich is \$6

6 0
3 years ago
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A student is driving a car at 60.0 miles/hour. what is its speed in m/s
hodyreva [135]
60 miles per hour.
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PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

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AveGali [126]
<span>Shaded region is when x is negative</span>

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