1. opinion
2. fact
3. opinion
4. opinion
5. fact
6. fact
im not sure if this is what you were asking but yeah
All you have to do is multiply by two, since calcium chloride has the chem. formula, CaCl2. For every 1 mole of CaCl2, you'll have 2 mole of chloride ions in solution.
B. Low blood pressure and drooling. If the user is tranquilized, he would not be able to hinder the production of saliva, leading to drooling. And if the victim was tranquilized, his heart would slow down, not speed up, resulting in a lower blood pressure.
Answer:
The mass percentage of bromine in the original compound is 81,12%
Explanation:
<u>Step 1: Calculate moles AgBr</u>
moles AgBr = mass AgBr / molar mass AgBr
= 0.8878 g / 187.77 g/mol
= 0.00472812 moles AgBr
⇒
Since 1 mol AgBr contains 1 mol Br-
Then the amount of moles Br- in the original sample must also have been 0.00472812 moles
<u>Step 2:</u> Calculating mass Br-
mass Br- = molar mass Br x moles Br-
= 79.904 g/mol x 0.00472812 mol
= 0.377796 g Br-
⇒
There were 0.377796 g Br- in the original sample
<u>Step 3:</u> Calculating mass percentage Br-
⇒mass percentage = actual mass Br- / total mass x 100%
% mass Br = 0.377796 g / 0.4657 g x 100 %
= 81.12%
Answer:
3.47 × 10¹ M⁻¹ h⁻¹
Explanation:
From the question, it's clearly depicted that it is a second order reaction rate.
NOW, rate constant for second order reaction can be given as:
k(t)=
Given that:
t = 24 hours
Let the initial concentration of reactant
Final concentration
∴
k(t)=
k(24)hours = 833.33 M⁻¹
k =
k = 34.72 M⁻¹ h⁻¹
k = 3.472 × 10¹ M⁻¹ h⁻¹
∴ the value of the rate constant (k) = 3.472 × 10¹ M⁻¹ h⁻¹