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vitfil [10]
4 years ago
6

What is the concentration of chloride ion in a 2.0 M solution of calcium chloride

Chemistry
2 answers:
mote1985 [20]4 years ago
4 0
CaCl2. This might be the answer
lbvjy [14]4 years ago
3 0
All you have to do is multiply by two, since calcium chloride has the chem. formula, CaCl2. For every 1 mole of CaCl2, you'll have 2 mole of chloride ions in solution.
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Which of the following explains why the lab safety policy specifically addresses loose clothing, contact lenses, and large, loos
valentina_108 [34]

Answer:

b. Loose clothing and jewelry is more likely to impede movement, or accidentally knock materials over, causing a spill or other accident.

Explanation:

Hello,

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3 0
3 years ago
What is The substance that could not be dissolved and has settled out of a solution
lys-0071 [83]

homogeneous mixture not pure, but is spread out the same throughout

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5 0
3 years ago
Which statement describes the periodic law?
mr_godi [17]
Answer is: elements in the same group have similar chemical properties.
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3 0
4 years ago
Read 2 more answers
What is the kinetic energy of a 100-kg object that is moving with a speed of 12.5 m/s?
miss Akunina [59]
Becasue KE= 1/2 mv squared

KE= 1/2 (100) 12.5 sqaured 
             50           156.25 =

                     7812.5 < is your answer 

Hopefully that makes sense and i did the math right.... 
8 0
4 years ago
Read 2 more answers
9. Thallium-208 has a half-life of 3.053 min. How long will it take for 120 g of it to decay
damaskus [11]

Answer:

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

Explanation:

Radioactive isotopes decay exponentially in time, the mass of the isotope (m(t)), in grams, is described by the formula in time (t), in minutes:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

m_{o} - Initial mass of the isotope, in grams.

\tau - Time constant, in minutes.

In addition, the time constant associated with the isotope decay can be described in terms of half-life (t_{1/2}), in minutes:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m(t) = 7.5\,g, m_{o} = 120\,g and t_{1/2} = 3.053\,min, then the time taken by the isotope is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{3.053\,min}{\ln 2}

\tau \approx 4.405\,min

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(4.405\,min)\cdot \ln \left(\frac{7.5\,g}{120\,g} \right)

t \approx 12.213\,min

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

4 0
3 years ago
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