The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
Read more about exponential functions at:
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Answer:
B. 100
Step-by-step explanation:
(m + n)^2
= m^2 + 2mn + n^2
Rearrange
(m^2 + n^2) + 2mn
Substitute
(68) + 2*16
= 68 + 32
= 100
Lets write down the information that we know.
Jessie has 7 stacks of 6 dimes, so Jessie has a total of 6*7 dimes
Dimes=7*6=42dimes
Jessie has 42 dimes, but then she found another one so lets add one more dime.
42+1=43 dimes
Jessie has 8 stacks of 5 nickels, so Jessie has 8*5 nickels
Nickels=8*5=40nickels
Jessie has 40 nickels, but then she found another one so lets add 1 to the total number of nickels.
40+1=41nickels
Now we can answer the question.
How many dimes and nickels does jessie have in all?
nickels+dimes=
41+43=84 coins
Jessie has 84 coins in total
Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
Answer:
103 msand is the most important thing to be aware of and that is 33454 for the test and of you I a 83838
Step-by-step explanation:
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