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Andrew [12]
3 years ago
5

Adam has the difference between two-thirds of bretts book and two thirds of charlies books.If brett has 72 books and charlie has

72 books how many books does adam have
Mathematics
1 answer:
melomori [17]3 years ago
6 0

Answer:

48

Step-by-step explanation:

Adam has 2/3 of books that brett and charlie have : 2/3 of 72 wich is 48

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S+2t=6. 3s-2t=2<br> Using elimination
Ludmilka [50]
For the first one, I will solve for t.
s + 2t = 6, first we isolate the t variable,
2t = -s + 6, divide both sides by 2,
t = -s/2 + 3, < There's your answer for 1!

Here's the second one,
3s - 2t = 2, subtract 3s from both sides,
-2t = 2 - 3s, divide both sides by -2,
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6 0
3 years ago
0.3125 can be written in the form p/q as
givi [52]
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4 years ago
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How long will it take for $2500 to double if it is invested at 6% annual interest compounded 6 times a year? Enter exact calcula
12345 [234]

Answer:

Part 1) t=11.610\ years

Part 2) t=11.552\ years

Step-by-step explanation:

Part 1) we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06\\n=6  

substitute in the formula above

5,000=2,500(1+\frac{0.06}{6})^{6t}  

2=(1.01)^{6t}  

Apply log both sides

log(2)=log[(1.01)^{6t}]

log(2)=(6t)log(1.01)  

solve for t

t=log(2)/[6log(1.01)]  

t=11.610\ years

Part 2) we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06  

substitute in the formula above

5,000=2,500(e)^{0.06t}

2=(e)^{0.06t}  

Apply ln both sides

ln(2)=ln[(e)^{0.06t}]

ln(2)=(0.06t)ln(e)

ln(2)=(0.06t)

t=ln(2)/(0.06)

t=11.552\ years

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4>f+6= f > -2

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