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musickatia [10]
2 years ago
13

a meal cost 32.75 and another meal cost 39.88 a person pays for bothe meals and leaves a 14% tip whats the total cost

Mathematics
2 answers:
mafiozo [28]2 years ago
4 0

Answer:

total cost = 77.82 including tax

Step-by-step explanation:

32.75+39.88= 72.63

72.63/14= 5.19

72.63+5.19

=77.82

kramer2 years ago
3 0

Answer:

if a person pays for both meal then

32.75+39.88

=159.75

noww

14%of 159.75

(14/100)x159.75

=22.36$

noww total cost

=159.75+22.36

=182.115$

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Select ALL the correct answers.
DaniilM [7]
Be:
Number of hours: n

<span>The cost of renting a bike for the first hour is $7:
n=1→f(n)=f(1)=$7

</span>He is charged $2.50 for every additional hour of renting the bike:
f(n)=f(n-1)+2.50, for <span>n ≥ 2
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f(1)=7; f(n)=f(n-1)+2.50, for <span>n ≥ 2 (sixth option)
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f(n)=f(1)+2.50(n-1)
f(n)=7+2.50(n-1)
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Answers:
Fifth option: f(n)=2.50n+4.50, and
Sixth option: f(1)=7; f(n)=f(n-1)+2.50, for <span>n ≥ 2</span>
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What is the decimal form of 3/8
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Read 2 more answers
The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

4 0
3 years ago
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