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2 years ago

a meal cost 32.75 and another meal cost 39.88 a person pays for bothe meals and leaves a 14% tip whats the total cost

Mathematics

2 answers:

mafiozo [28]2 years ago

4 0

Answer:

total cost = 77.82 including tax

Step-by-step explanation:

32.75+39.88= 72.63

72.63/14= 5.19

72.63+5.19

=77.82

kramer2 years ago

3 0

Answer:

if a person pays for both meal then

32.75+39.88

=159.75

noww

14%of 159.75

(14/100)x159.75

=22.36$

noww total cost

=159.75+22.36

=182.115$

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Answer:

The answer is A.

Step-by-step explanation:

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Write the first five digits of 1/7 in base 9 expression

kaheart [24]

Compare 1/7 to consecutive multiples of 1/9. This is easily done by converting the fractions to a common denominator of LCM(7, 9) = 63:

1/9 = 7/63

2/9 = 14/63

while

1/7 = 9/63

Then 1/7 falls between 1/9 and 2/9, so 1/7 = 1/9 plus some remainder. In particular,

1/7 = 1/9¹ + 2/63.

We do the same sort of comparison with the remainder 2/63 and multiples of 1/9² = 1/81. We have LCM(63, 9²) = 567, and

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while

2/63 = 18/567

Then

2/63 = 2/9² + 4/567

1/7 = 1/9¹ + 2/9² + 4/567

Compare 4/567 with multiples of 1/9³ = 1/729. LCM(567, 9³) = 5103, and

1/9³ = 7/5103

2/9³ = 14/5103

3/9³ = 21/5103

4/9³ = 28/5103

5/9³ = 35/5103

6/9³ = 42/5103

while

4/567 = 36/5103

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4/567 = 5/9³ + 1/5103

and so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/5103

Next, LCM(5103, 9⁴) = 45927, and

1/9⁴ = 7/45927

2/9⁴ = 14/45927

while

1/5103 = 9/45927

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1/5103 = 1/9⁴ + 2/45927

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1/9⁵ = 7/413343

2/9⁵ = 14/413343

3/9⁵ = 21/413343

while

2/45927 = 18/413343

Then

2/45927 = 2/9⁵ + remainder

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Then the base 9 expansion of 1/7 is

0.12512..._9

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2 years ago

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Multiply both sides by 11 :

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Divide both sides by " log(1/2) " :

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That's the time it takes for any-size sample of this substance
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