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Tems11 [23]
3 years ago
12

Pls help me solve it!

Mathematics
1 answer:
vekshin13 years ago
3 0

Answer:

A= 40°

B= 35°

C= 15°

Step-by-step explanation:

Since it says if the triangles were accurately drawn, then A would be the same  degree as Q. C would be the same degree as P. B would be the same degree as R. Since R's degree is missing I knew that a obtuse triangle was 90°. I added 40+15 and got 55. Then i subtracted 90-55 and got 35. So the unknown value would be 35°.

I hope this helps.

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Answer:

The standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Step-by-step explanation:

We know that:

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

x^2\:+\:10x\:+\:6y\:=\:47

Rewriting the equation in the standard form

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

where

vertex (h, k) = (-5, 12)

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